There are many answers to this question. The first step is normally a reboot, second, I would check witch task or service is taking up all the CPU cycles and check the system and error logs. The list goes on... I'm not sure how detailed you want to get.
Complete Question:
Assume that an array of Integers named a that contains exactly five elements has been declared and initialized. In addition, an int variable j has also been declared and initialized to a value somewhere between 0 and 3.
Write a single statement that assigns a new value to the element of the array indexed by j. This new value should be equal to twice the value stored in the next element of the array (i.e. the element after the element indexed by j ). Do not modify any other elements of the array!
Answer:
a[j] = 2 * a[j+1];
Explanation:
Since the array is named a and its indexes are referenced by the variable j
it means the elements of the array will be a[j] for (j=0; j=1;j=2).
The first element in the array (j=0) will be a[0], second element will be a[1] and so on.
The statement a[j] = 2 * a[j+1]; assigns a new value to the element of the array indexed by j, the value is equal to twice the value stored in the next element of the array (j+1).
