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3 years ago

Which of the following is an experiment?

2 answers:

8 0

D! because when you record something you will probably analyze the results and those are two big KEY components of an Experiment! <span />

Tresset [83]3 years ago

6 0

Answer: D) recording the high and low temperature at a particular location every day.

Explanation:

A experiment is a process which is conducted or performed to either support, refute or validate the hypothesis. It involves the detail repeatable procedure and the logical analysis of the outcomes of the results. It involves different variables which are compared to obtain the outcome of the experiment. For example the amount of water used everyday responsible for the plant height.

Among the options given, D) recording the high and low temperature at a particular location every day. is the correct option, temperature is a variable in the experiment. The change in the daily temperature of a location can be noted as observation of the experiment. This observation can be used to record the average temperature of the location.

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Butane is also a molecular compound. what is its formula? how many atoms does it contain?

pishuonlain [190]

The formula of butane is C4H10 but I don't how many atoms it contains though

5 0

3 years ago

For the following reaction, 2 SO2(g) + O:(g) 2 SO,(g) the equilibrium constant, K, is 1.32 at 627°C. What is the equilibrium con

cupoosta [38]

Answer:

1.15

Explanation:

2SO₂ + O₂ ⟶ 2SO₃; K =1.32

SO₂ + ½O₂ ⟶ SO₃; K₁ = ?

When you divide an equation by 2, you take the square root of its equilibrium constant.

K₁ = √1.32 = 1.15

The equilibrium constant is 1.15.

8 0

3 years ago

If f(x)=x^2 and g(x)=2x+3, what is f(g(x))

IgorC [24]

Answer:

$\huge\boxed{f(g(x)) = 4x^2 + 12x + 9}$

Explanation:

In its raw form, function notation essentially represents an equation with only one unknown variable, expressed in terms of another. Thus, f(x) = x² + 7x can be expressed as

g(x) = 2x + 3

f(g(x)) = (2x + 3)²

f(g(x)) = 4x² + 12x + 9

Hope it helps :) and let me know if you want me to elaborate.

6 0

2 years ago

Read 2 more answers

The rate constant k for a certain reaction is measured at two different temperatures temperature 376.0 °c 4.8 x 108 280.0 °C 2.3

9966 [12]

Answer:

The activation energy for this reaction = 23 kJ/mol.

Explanation:

Using the expression,

$\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )$

Where,

$k_1\ is\ the\ rate\ constant\ at\ T_1$

$k_2\ is\ the\ rate\ constant\ at\ T_2$

$E_a$ is the activation energy

R is Gas constant having value = 8.314×10⁻³ kJ / K mol

$k_2=2.3\times 10^8$

$T_2=280\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (280 + 273.15) K = 553.15 K

$T_2=553.15\ K$

$k_1=4.8\times 10^8$

$T_1=376\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (376 + 273.15) K = 649.15 K

$T_1=649.15\ K$

So,

$\left(\ln \left(\:\frac{4.8\times \:\:\:10^8}{2.3\times \:\:\:10^8}\right)\right)\:=-\frac{E_a}{8.314\times \:10^{-3}\ kJ/mol.K}\times \:\left(\frac{1}{649.15\ K}-\frac{1}{553.15\ K}\right)$