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vfiekz [6]
2 years ago
14

HELP!!!

Chemistry
2 answers:
pshichka [43]2 years ago
4 0

Answer:

2.53kpa

Explanation:

p1*v1/t1 = constant

the constant can be changed to p2*v2/t2

v2 can be removed from equation as it is constant

Kitty [74]2 years ago
3 0

Answer:

2.54kpa

Explanation:

p*v/t = constant

6.58/539=p2/2111

p2=211(6.50/539)

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1 x 10^-7 or 7

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pH=-log(H+)

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Simora [160]

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2 years ago
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It was calculated that 4.3mL of 0.417 M HCl is required to titrate 11.9 mL of 0.151 M Mg(OH)2. Show evidence 2 HCl(aq) + Mg(OH)2
Lapatulllka [165]

Answer:

See explanation.

Explanation:

Hello,

In this case, for the described chemical reaction:

2 HCl(aq) + Mg(OH)2(aq) → MgCl2(aq) + 2 H2O(l)

We can notice there is a 2:1 molar ratio between the moles of hydrochloric acid and magnesium hydroxide, therefore, at the equivalence point:

n_{HCl}=2*n_{Mg(OH)_2}

And in terms of volumes and concentrations we verify:

V_{HCl}M_{HCl}=2*V_{Mg(OH)_2}M_{Mg(OH)_2}

So we use the given data to proof it:

4.3mL*0.417M=2*11.9mL*0.151M\\1.793=3.594

Therefore, we can conclude the data is wrong by means of the 2:1 mole ratio that for sure was not taken into account. This is also supported by the fact that normalities are actually the same, but the nomality of magnesium hydroxide is the half of the hydrochloric acid normality since the acid is monoprotic and the base has two hydroxyl ions.

Best regards.

4 0
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