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vfiekz [6]
2 years ago
14

HELP!!!

Chemistry
2 answers:
pshichka [43]2 years ago
4 0

Answer:

2.53kpa

Explanation:

p1*v1/t1 = constant

the constant can be changed to p2*v2/t2

v2 can be removed from equation as it is constant

Kitty [74]2 years ago
3 0

Answer:

2.54kpa

Explanation:

p*v/t = constant

6.58/539=p2/2111

p2=211(6.50/539)

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Which of the following is most likely to dissolve in NH3? A) CO2 B) CH4 C) H2S D) BH3
dem82 [27]

Answer:

C) H2S

Explanation:

In chemistry, the dissolution of one substance in another is dependent on the magnitude of intermolecular interaction between the two substances.  Hence, if two substances do not interact in one way or the other, then one can not dissolve the other.

Let us consider the fact that NH3 is a polar molecule and it is a general principle that like dissolves like. Hence, only H2S which is also a polar molecule can effectively interact with  NH3 due to dipole-dipole interaction between the two molecules.

Also, ammonia reacts with hydrogen sulphide as follows;

2NH3 + H2S → (NH4)2S

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5 0
3 years ago
Compare and contrast the functions of each of the following types of flasks: filter, Erlenmeyer, volumetric.
harkovskaia [24]
The Erlenmeyer Flask was <span>introduced in 1861 by German chemist </span>Emil Erlenmeyer and is shaped like a cone. This has a triangular shape and mouth wide for it to be easier to pour and store liquids. The Volumetric flask<span> is used for preparing liquids with volumes of high precision. It has a </span>pear-shaped body and a long neck with a circumferential fill line. The Filter Flask is also known as the <span>A Büchner </span><span>flask. It is like the Erlenmeyer but this one is thick-walled and has a special arm in the side. It is used for filtering liquid. </span>
4 0
3 years ago
Write the empirical formula for at least four ionic compounds that could be formed from the following ions: NO3, Pb^4+, NH4, SO4
Alisiya [41]

Explanation:

here's the answer to your question

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5 0
3 years ago
A sample of g of pure aluminum metal is added to mL of M hydrochloric acid. The volume of hydrogen gas produced at standard temp
MArishka [77]

Answer:

V = 11.2L are produced

Explanation:

... <em>Sample of 27g of pure aluminium, 3added to 333 mL of 3.0 M HCl..</em>

Based on the chemical reaction:

2Al(s) + 6HCl(aq) → 2AlC₃(aq) + 3H₂(g)

<em>Where 3 moles of hydrogen are produced when 6 moles of hydrochloric acid reacts with 2 moles of Al.</em>

<em />

To solve this question, we need to determine limiting reactant converting each reactant to moles. With limiting reactant and the chemical reaction we can find moles of hydrogen and its volume at STP (T=273.15K; P=1atm), thus:

<em>Moles Al-Molar mass: 26.98g/mol-:</em>

27g * (1mol / 26.98g) = 1mol of Al

<em>Moles HCl:</em>

333mL = 0.333L * (3mol/L) = 1mol HCl

For a complete reaction of 1 mole of HCl are required:

1mol HCl * (2mol Al / 6mol HCl) = 0.333 moles of Al. As there is 1 mole of Al, Al is in excess and <em>HCl is limiting reactant.</em>

<em />

Moles of Hydrogen produced are:

1mol HCl * (3 moles H₂ / 6 mol HCl) = 0.5moles H₂ are produced.

Using ideal gas law:

PV = nRT

V = nRT/P

<em>Where V is volume</em>

<em>n are moles: 0.5mol</em>

<em>R is gas constant: 0.082atmL/molK</em>

<em>T is absolute temperature: 273.15K</em>

<em>P is pressure: 1atm.</em>

<em />

Solving for V:

V = 0.5mol*0.082atmL/molK*273.15K / 1atm

<h3>V = 11.2L are produced</h3>
3 0
3 years ago
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