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Contact [7]
3 years ago
7

A box contains 19 large marbles and 10 small marbles. Each marble is either green or white. 8 of the large marbles are green, an

d 4 of the small marbles are white. If a marble is randomly selected from the box, what is the probability that it is small or white? Express your answer as a fraction or a decimal number rounded to four decimal places.

Mathematics
1 answer:
notsponge [240]3 years ago
7 0

Answer:

25/29

Step-by-step explanation:

see the attached picture.

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Will give brainliest
vlada-n [284]

Answer:

im not sure?

Step-by-step explanation:

7 0
3 years ago
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Find the dimensions of the cube,<br> Volume = 64 in
Ksivusya [100]

Answer:

4 in

Step-by-step explanation:

volume = 64 in³

side = cubic root of 64 in³

side = 4 in

Check: If a cube has side 4 in, then its volume is 4 in × 4 in × 4 in = 64 in³.

This shows that the answer 4 in is correct.

4 0
2 years ago
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Consider this expression.<br> m² - 7 + n²<br> When m = -2and n = 5, the value of the expression is
Rasek [7]

Answer:

22

Step-by-step explanation:

Just substitute and solve!

(-2)^2 - 7 + (5)^2 = 4 - 7 + 25 = 22

hope this helps! <3

8 0
2 years ago
Please help the answer are <br> 12<br> 4<br> X<br> X+4<br> -16<br> 16<br> X+12<br> X^2
Lorico [155]
Step 1:
x² + 4x = 192

Step 2:
Take x common:
x ( x + 4) = 192

Length is x and width is x+4

Step 3:

x² + 4x - 192 = 0

Step 4:

x² + 16x - 12x - 192 = 0
x(x+16) - 12(x+16) = 0
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⇒ x=12, x=-16

Because the length can't be -16, the length is 12.
7 0
3 years ago
Read 2 more answers
For any nonnegative real number.
frutty [35]

Answer:

A

Step-by-step explanation:

We know that \sqrt{b}=b^{1/2}.

We also know that (a^b)^c=a^{bc}.

We can combine these facts to get (\sqrt{b})^2=(b^{1/2})^2=b^{1/2*2}=b^{1}=b.

So, the answer is \boxed{A} and we're done!

<em>Note: the non-negative part or the equation comes from the fact that you assume the square root of a negative number doesn't exist. You will change this assumption later in the year, or in further years.</em>

5 0
3 years ago
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