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kirill [66]
2 years ago
6

What is the nth term rule for the liner sequence below 15,7,-1,-9,-17

Mathematics
1 answer:
Volgvan2 years ago
8 0

Answer:

-8n+7

Step-by-step explanation:

the difference between the values is 8, as it decreases by 8, it withh be 8n

It does not start at 8 though, so you do 15-8 to find the different which is added on which is 7 in this case

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A bowl contains blueberries and strawberries. There are a total of 48 berries in the bowl. The ratio of blueberries to strawberr
Dvinal [7]

Answer:

a. 36 blueberries and 12 strawberries

b. 16 blueberries and 4 strawberries

Step-by-step explanation:

The computation of each berry in the bowl is shown below;

a. Total 48 berries

The Ratio of blueberries to strawberries is 9:3

So, the blueberries is = 48 × 9 ÷ (9  + 3) = 36

And, the strawberries is = 48 × 3 ÷ (9 + 3) = 12

b. Total 20 berries

The Ratio of blueberries to strawberries is 4:1

So, the blueberries is = 20 × 4 ÷ (4 + 1) = 16

And, the strawberries is = 20 × 1 ÷ (4 + 1) = 4

6 0
2 years ago
A sole proprietorship is worth w dollars. The owner loses a lawsuit
KIM [24]

Answer:

y - w

Step-by-step explanation:

<u>Step 1</u>

The owner can sell the sole proprietorship for w dollars, so you need to find out what remains of y to find the answer.

<u>Step 2</u>

Hence: y - w shows the remainder.

3 0
3 years ago
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Why am I still single? It quarantine and no one is hmu.
Sergio [31]

Answer:

Apply yourslef! Don't wait for people to text you, especially if you like a certain person. Honestly, find all the people you might like and text them at the same time and start a conversation and you can take it from there!

Step-by-step explanation:

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3 years ago
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Hi please help me thanksss<br>pls provide workings too thanks :)​
anygoal [31]

Step-by-step explanation:

Search for questions & chapters

Class 11

>>Maths

>>Trigonometric Functions

>>Trigonometric Equations

>>Solve for x: sin x + sin 2x...

Question

Bookmark

Solve for x:sinx+sin2x+sin3x=cosx+cos2x+cos3x in the interval 0≤x≤2π.

Medium

Solution

verified

Verified by Toppr

We write the given equation as

(sinx+sin3x)+sin2x=(cosx+cos3x)+cos2x

or 2sin2xcosx+sin2x=2cos2xcosx+cos2x

or sin2x(2cosx+1)=cos2x(2cosx+1)

or (sin2x−cos2x)(2cosx+1)=0

∴sin2x−cos2x=0 or 2cosx+1=0

If sin2x−cos2x=0, then tan2x=1,

Hence 2x=nπ+π/4

or x=(4n+1)

8

π

.(1)

If 2cosx+1=0, then cosx=−1/2 (2)

∴x=2nπ±

3

2π

or x=

3

6n±2

π

We seek values of x in the interval 0≤x≤2π

In this interval (1) gives

x=π/8,5π/8,9π/8,13π/8. (n=0,1,2,3)

and (2) gives x=2π/3,4π/3. (for n=0,1)

Thus we get the answer

x=π/8,5π/8,2π/3,9π/8,4π/3,13π/8.

4 0
2 years ago
Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol
aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

P(A\cap B)=P(A)\times P(B)

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0
3 years ago
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