(A) ANSWER: 0%. A homozygous dominant seal would be "WW" (homozygous dominant = 2 CAPITAL letters).
Answer:
the movement of water is from A to B thus making equilibrium water in B must be more so that water is balanced in both thus the water in B will be 13 and in A , 7 cm so , the answer is A it has 7 cm of water
Explanation:
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Answer:
The best way to eliminate the wind is to build barriers.
Explanation:
As you may already know, the wind is a large-scale flow of gases. This flow is palpable and can be prevented from entering certain places by building physical barriers that block the flow. In this case, the construction of barriers prevents the wind from advancing and reaches a certain region, because it causes the wind to crash against this barrier and be pushed back, prevented from advancing.
Answer:
The correct answer is option d.
Explanation:
The production of Acetyl-CoA takes place by the dissociation of both carbohydrates and lipids in the process of glycolysis and beta-oxidation. It then moves into the TCA cycle in the mitochondria and combines with oxaloacetate to give rise to citrate.
In the given case, no labeling will be found in the acetyl-CoA. The labeled C3 and C4 carbon of glucose signify the carboxyl carbon of pyruvate. In the succeeding reactions of the transformation of pyruvate to acetyl-CoA, the carboxyl carbon gets lost in the form of carbon dioxide. Thus, acetyl-CoA does not comprise any labeled C3 and C4 of glucose.