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3 years ago

ILL MARK AS BRAINLESS PLS HELP HURRY

Mathematics

2 answers:

BartSMP [9]3 years ago

8 0

Answer: the first one is 4/3. The second one is 8/20. The third one is 8/8. The fourth one is 7/13!

Step-by-step explanation:

MAXImum [283]3 years ago

3 0

Answer:

First one is 4/3. The second one is 8/20. The third one is 8/8. The fourth one is 7/13!!! :)))

Step-by-step explanation:

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Step-by-step explanation:him

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3 years ago

What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

Step(i):-

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

step(ii):-

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

step(iii):-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

Conclusion:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

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3 years ago

What are skew lines

taurus [48]

Answer: Skew lines are two lines that do not intersect and are not parallel. A simple example of a pair of skew lines is the pair of lines through opposite edges of a regular tetrahedron.

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lyudmila [28]

Answer:

C. Undefined

Step-by-step explanation:

Any vertical line is going to have an undefined slope. Plug in any two points from that line, and the formula will give you an undefined number.

Hope this helps!

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3 years ago