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Pavel [41]
2 years ago
10

ILL MARK AS BRAINLESS PLS HELP HURRY

Mathematics
2 answers:
BartSMP [9]2 years ago
8 0

Answer: the first one is 4/3. The second one is 8/20. The third one is 8/8. The fourth one is 7/13!

Step-by-step explanation:

MAXImum [283]2 years ago
3 0

Answer:

First one is 4/3. The second one is 8/20. The third one is 8/8. The fourth one is 7/13!!! :)))

Step-by-step explanation:

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What is the quotient (6x4 − 15x3 + 10x2 − 10x + 4) ÷ (3x2 + 2)?
Alexandra [31]

Answer:

The quotient of (6x4 + 15x3 + 10x2 + 10x + 4) ÷ (3x2 + 2)

is 2x2 + 5x + 2.

Step-by-step explanation:

6 0
2 years ago
4.2kg of oranges are £8.76. How much does 2kg cost
seropon [69]

Answer:

x = 4.17

Step-by-step explanation:

We can use a ratio to solve

4.2 k                  2 k

---------------- = ---------------

8.76                     x

Using cross products

4.2 * x = 2 * 8.76

4.2x =17.52

Divide by 4.2

x=4.17

8 0
3 years ago
Read 2 more answers
A 3-pound tub of butter at n dollars per pound costs $3.85. 3n = 3.85 3 - n = 3.85 3 + n = 3.85 3/n = 3.85
Elis [28]
Given:
3-pound tub of butter costs $3.85

3.85/3 = 1.2833 per pound.

3n = 3.85

3(1.2833) = 3.85
3.8499 = 3.85
3.85 = 3.85
7 0
3 years ago
Read 2 more answers
The graph shows two lines, A and B. A graph is shown with x- and y-axes labeled from 0 to 6 at increments of 1. A straight line
mixas84 [53]
( Part A: Ok 2,6 and 6,2 and 0,3 and 4.5,6 you can add 2,6 and every other number with part b which is 2,6 +0,3= 2,3 and also 2,6+4.5,6= 6.5,12 and you can do the same with 6,2 and you will get  6,5 and 10.5,8) 
(Part B: 2,3^6.5,12^6,5^10.5,8)
~Riley Hope this helped :P

7 0
3 years ago
Komodo dragons are the heaviest lizards on earth. A baby Komodo dragon is 1 3/4 feet long when it hatches. It’s mother is 8 3/4
sukhopar [10]

Answer:

An adult male Komodo dragon is 10\frac12 feet.

Therefore the male is 1\frac34 feet longer than the mother.

Step-by-step explanation:

Given that,

A baby dragon is 1\frac34 feet long.

It's mother is 8\frac34 feet.

An adult male Komodo dragon is 6 times as long as the baby Komodo dragon.

So, an adult male Komodo dragon is =(6×1\frac34 ) feet

                                                          =6\times \frac74 feet

                                                          =\frac61\times \frac74 feet

                                                         = \frac {21}2 feet.

                                                         =10\frac12 feet.

\therefore 10\frac 12- 8\frac34

=\frac{21}{2}-\frac{35}4

=\frac{21\times 2-35\times 1}{4}

=\frac{42-35}{4}

=\frac74

=1\frac34

Therefore the male is 1\frac34 feet longer than the mother.

4 0
3 years ago
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