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Hatshy [7]
3 years ago
14

What is 2 + 2(3+4) - (4-1) x (5+6)

Mathematics
2 answers:
Dahasolnce [82]3 years ago
8 0
Just going in order of BIDMAS I got -14

kaheart [24]3 years ago
5 0
2+2(3+4)-(4-1)×(5+6)
=2+2(7)-3×11
=2+14-33
=16-33
=-17
the ans is -17

hope it helps~
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Write an equation of a line whose graph is parallel to the graph of y=3x-10.
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Y=3x plus or minus any number that is not 10.

The slope of your function has to stay 3x to be parallel with the function given. Just change the y-intercept (also known as the B value) to a number other than -10.
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Step-by-step explanation:

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The perimeter of a rectangle is 36m. If its length is increased by 1m and the width is increased by 2m, its area will increase b
maw [93]

Answer:

  80 m^2

Step-by-step explanation:

The given information lets you write two equations involving length (x) and width (y).

  • 2(x +y) = 36 . . . . the perimeter is 36 m
  • (x+1)(y+2) -xy = 30 . . . . increasing the length and width increases area

The second of these equations simplifies to another linear equation, giving a system of linear equations easily solved.

  xy +y +2x + 2 -xy = 30

  2x +y = 28 . . . . . . . subtract 2

Dividing the first equation by 2 gives

  x +y = 18

and subtracting this from the above equation gives ...

  (2x +y) -(x +y) = 28 -18

  x = 10

Then

  y = 18 -10 = 8

The area of the original rectangle is xy = 10·8 = 80 m^2.

4 0
3 years ago
Melissa makes necklaces and sells them online. She charges $88 per necklace. Her monthly expenses are $3,745. How many necklaces
Dovator [93]
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4 0
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Solve the system by using a matrix equation (Picture provided)
Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]

A= \left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}4\\2\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

                                    = (-42)-(-40)

                                    = (-42) + 40 = -2

so, |A| = -2

Adj A=  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]/ -2

A⁻¹ =  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]

X= \left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]

X= \left[\begin{array}{c}12-4\\20-7\end{array}\right]

X= \left[\begin{array}{c}8\\13\end{array}\right]

x= 8, y= 13

solution set= (8,13).

Option b is correct.

3 0
3 years ago
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