The general term of an arithmetic sequence is
an = a1 +(n-1)d
Your sequence has first term a1 = 11 and common difference d = 4. Then the general term is
an = 11 + (n-1)*4
The simplest form of the general term is
an = 7 + 4n
Answer:
-19 y^2 + 18 x y + 13 x^2
Step-by-step explanation:
Simplify the following:
16 x^2 + 15 x y - 19 y^2 - (3 x^2 - 3 x y)
Factor 3 x out of 3 x^2 - 3 x y:
16 x^2 + 15 x y - 19 y^2 - 3 x (x - y)
-3 x (x - y) = 3 x y - 3 x^2:
16 x^2 + 15 x y - 19 y^2 + 3 x y - 3 x^2
Grouping like terms, 16 x^2 + 15 x y - 19 y^2 - 3 x^2 + 3 x y = -19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2):
-19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2)
x y 15 + x y 3 = 18 x y:
-19 y^2 + 18 x y + (16 x^2 - 3 x^2)
16 x^2 - 3 x^2 = 13 x^2:
Answer: -19 y^2 + 18 x y + 13 x^2
Answer:
26V + 2
Step-by-step explanation:
This is the same as saying f(g(x)), where x = 26
First, lets figure out what g(x) is equal to when x = 26
g(26) = V(26) - 1 = 26V - 1
Now we input 26V - 1 into f(x) for x
f(26V-1) = (26V-1) + 3 = 26V + 2
4$ would be the cost of the item
<h2>Answer </h2>
D. 6x>_360; x>_60
<h2>Explanation</h2>
Let 
be amount you will save each weeks
Since we know that you are saving over a period of 6 weeks, you will save 
.
We also now that your goal is to save at least $360.00 over the period of 6 weeks, so saving more than $360.00 will be very desirable, but the goal is to save $360.00. We can rephrase this as: You need to save $360.00 or more; we can say the same using the inequality symbol 
(greater on equal than)
Now we can combine our tow parts using the inequality symbol:
To simplify divide both sides by 6:
You need to save at least $60 per week, so the correct answer is D. 6x>_360; x>_60
