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faltersainse [42]
3 years ago
7

Write an equation of a line whose graph is parallel to the graph of y=3x-10.

Mathematics
2 answers:
Rzqust [24]3 years ago
7 0
Y=3x plus or minus any number that is not 10.

The slope of your function has to stay 3x to be parallel with the function given. Just change the y-intercept (also known as the B value) to a number other than -10.
Diano4ka-milaya [45]3 years ago
5 0

Answer:  

The equation of line parallel to the given equation of line : y = 3x + 4

Step-by-step explanation:

The equation of the line is given to be :

y = 3x - 10

Now, on comparing the given equation of line with the standard equation of line in slope intercept form : y = mx + c

where m is the slope of the line

So, Slope of the given equation of line = 3

Now, Since parallel lines never intersect each other

⇒ The slope of parallel lines are equal to each other

So, The required equation of parallel line is of form : y = 3x + c

Hence, The equation of line parallel to the given equation of line : y = 3x + 4

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7 times a number is 18 less than the square of that number. Find the positive solution.
Arte-miy333 [17]
So 7 x = x2 -18 so you get the quadratic x^2 -7x -18 and then get 2 x -9= -18 and 2 + -9 = -7 so you get (x + 2) ( x - 9) so the positive solution would be x-9 = 0 so x= 9. Hope this helps :)
7 0
3 years ago
Given that x= –1/2 and y = 4 , evaluate 3x²y + xy²​
zvonat [6]

Answer:

-5

Step-by-step explanation:

3x²y + xy²​

Let x = -1/2 and y = 4

3(-1/2)^2 (4) + (-1/2) (4)^2

Exponents first

3(1/4) (4) + (-1/2) 16

Multiply

3 - 8

Subtract

-5

​

7 0
3 years ago
Read 2 more answers
Five names for number 64
yanalaym [24]
Sixty four

6 tens 4 ones

64 ones

60+4

8 to the power of 2

5 0
3 years ago
Help please i need the correct answer
aivan3 [116]

Answer:

the first one will be a <u>positive correlation</u>

the answer for the second Q will be 16

Step-by-step explanation:

have a nice day

5 0
2 years ago
PLEASEEE HELP MEEEE<br><br>NO LINKSSS
Artemon [7]

Answer:

\huge\boxed{(2,\ 3);\ (-1,\ 6)}

Step-by-step explanation:

f(x)=x^2-2x+3\to y=x^2-2x+3\\f(x)=-x+5\to y=-x+5\\\\\left\{\begin{array}{ccc}y=x^2-2x+3&(1)\\y=-x+5&(2)\end{array}\right

substitute (1) to (2):

x^2-2x+3=-x+5     add x to both sides

x^2-2x+x+3=-x+x+5

x^2-x+3=5        subtract 5 from both sides

x^2-x+3-5=5-5

x^2-x-2=0\\\\x^2+x-2x-2=0\\\\x(x+1)-2(x+1)=0\\\\(x+1)(x-2)=0\iff x+1=0\ \vee\ x-2=0\\\\\boxed{x=-1\ \vee\ x=2}

substitute the values of x to (2):

x=-1\\\\y=-(-1)+5=1+5=6\\\\\huge\boxed{(-1,\ 6)}\\\\x=2\\\\y=-2+5=3\\\\\huge\boxed{(2,\ 3)}

3 0
3 years ago
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