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anastassius [24]
3 years ago
7

Find the value of the expression 4a to the fourth power - 2b squared +40 when a =2 and b=7

Mathematics
1 answer:
Tom [10]3 years ago
3 0
4a^4 -2b^2 +40
a=2
b=7
4(2)^4 -2(7)^2 +40
PEMDAS is what your gonna use to solve this you go from right to left

First is P which is parentheses which is none
second is E which stands for exponents
4(32)-2(49)+40
now MD multiply or divide
128-98+40
now add or subtract
30+40
last one 
70 this is your answer i hope

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The endpoints of line segment RS are R(-2,-1), and S (2,3). Find the coordinates of the midpoint of line segment RS.
madam [21]
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6 0
3 years ago
Solve for x<br><img src="https://tex.z-dn.net/?f=4%20%20%7Bx%7D%5E%7B2%7D%20%20%3D%207x%20%2B%202" id="TexFormula1" title="4 {x
Alina [70]

\bf 4x^2=7x+2\implies 4x^2-7x-2=0\implies (4x+1)(x-2)=0 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4x\cdot x=\boxed{4x^2}~\hfill (1)(-2)=\boxed{-2}\hfill (4x\cdot -2)+(1\cdot x)=\boxed{-7x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} 4x+1=0\implies 4x=-1\implies &x=-\cfrac{1}{4}\\[1em] x-2=0\implies &x=2 \end{cases}

7 0
2 years ago
What percent of the first 20 natural numbers are prime numbers?
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3 0
3 years ago
Read 2 more answers
A cylindrical can is to have volume 1500 cubic centimeters. determine the radius and the height which will minimize the amount o
Degger [83]
Assuming R and H:
So volume is pir^2 * H = 1500 and H = 1500/(pir^2)  while surface area is A= 2pir*H + 2pir^2 
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For A to take minimum, get the derivative 4pir - 3000/R^2 and let it be 0 
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r = cbrt(3000/(4pi)) ≈ 6.20
h = 1500/(pi(6.20)^2) ≈ 12.42
8 0
3 years ago
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