Subtract 3x from
both sides: −2y = −3x + 16; divide
both sides by −2: y x = − 3
2 8.
Answer:
the company must buy 22 gallons to paint this entire area
Step-by-step explanation:
The circumference of the tank is given and is C = 2(pi)r, where r is the area.
118 ft
Here the circumference is C = 2(pi)(r) = 118 ft, which leads to r = ------------ ≈
18.79 ft ≈ r 2(pi)
The area of the sides is A = (circumference)(height), or approximately
(118 ft)(50 ft) = 5900 ft², and the area of the top is A = πr², which here comes to (π)(18.79 ft)² ≈ 1109 ft². Combining these two sub-areas, we get:
A(total) = 1109 ft² + 5900 ft² ≈ 7009 ft²
To determine how many gallons of paint will be needed to paint only the top and sides, we divide 7009 ft² by the coverage rate, which is
320 ft²
-----------
1 gallon
which results in:
7009 ft²
---------------------- ≈ 21.9 gallons
320 ft² / gallon
Since the paint comes only in full gallon cans, the company must buy 22 gallons to paint this entire area.
Answer:
Step-by-step explanation:
The axes x and y are calibrated in 0.25
If the circle is carefully considered, the radius r of the circle is:
r = -1.25 - (-2)
r = 0.75 units
The equation of a circle is given by:
The center of the circle (a, b) = (-2, -2)
Substituting (a, b) = (-2, -2) and r = 0.75 into the given equation:
Answer:
53.3 degrees
Step-by-step explanation:
∆DEF and ∆RSQ are similar. We know this, because the ratio of their corresponding sides are equal. That is:
DE corresponds to RS
EF corresponds to SQ
DF corresponds to RQ.
Also <D corresponds to <R, <E corresponds to <S, and <F corresponds to <Q.
The ratio of their corresponding sides = DE/RS = 6/3 = 2
EG/SQ = 8/4 = 2
DF/RQ = 4/2 = 2.
Since the ratio of their corresponding sides are equal, it means ∆DEF and ∆RSQ are similar.
Therefore, their corresponding angles would be equal.
Thus, m<Q = m<F
Let's find angle F
m<F = 180 - (98 + 28.7)
m<F = 53.3°
Since <F corresponds to <Q, therefore,
m<Q = 53.3°
Answer:
first, you want to start with the b (-3) graph on the y-axis. after that, since your x is 2 you will start from -3 on the y-axis and go up 2 and to the left once and keep doing that till you run out of space. then go back to the -3 on the y-axis and go down 2 and to the right once
