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SOVA2 [1]
3 years ago
15

write the equation for the quadratic function that has the vertex at (1,3) and passes through the point (0,5)

Mathematics
1 answer:
Kisachek [45]3 years ago
4 0
For this quadratic, its vertex form f(x) = a(x-h)^2+k is f(x) = a(x-1)^2+3.

To find the value of a, plug in (0,5) and solve. 

5 = a(0-1)^2+3 \\ a = 2

The final equation in vertex form is f(x) = 2(x-1)^2+3.

In standard form f(x) = ax^2+bx+c, the function is f(x) = 2x^2-4x+5.
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