write the equation for the quadratic function that has the vertex at (1,3) and passes through the point (0,5)

1 answer:

4 0

For this quadratic, its vertex form $f(x) = a(x-h)^2+k$ is $f(x) = a(x-1)^2+3$ .

To find the value of a, plug in (0,5) and solve.

$5 = a(0-1)^2+3 \\ a = 2$

The final equation in vertex form is $f(x) = 2(x-1)^2+3$ .

In standard form $f(x) = ax^2+bx+c$ , the function is $f(x) = 2x^2-4x+5$ .

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Answer:

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Step-by-step explanation:

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