The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
Answer:
B
Step-by-step explanation:
Angle P and Angle Q are co- interior angles so they add up to 180 degrees
If angle P is 116, then:
116+ x= 180
(x= Angle Q)
x=180-116
x=64
Answer:
Step-by-step explanation:
This is classic right triangle trig. The height of the hill is 78.4 which serves as the side opposite the reference angle of 23 degrees. The side we are looking for is the hypotenuse of that triangle. The trig ratio that relates the side opposite a reference angle to the hypotenuse of the right triangle is the sin ratio. Setting it up using our values:
, where x is the unknown length of the hypotenuse. Solving for x:
Make sure your calculator is in degree mode before entering this in. You will get a length of the hypotenuse as 200.649 feet, so choice A.
Mean: so basically you add up all the numbers (5+12+1+5+7=30) and divide the sum (30) with how many numbers there are (5) so 30/5=6
mode: mode is numbers repeated, since there are two 5's it is the mode (you may also have multiple modes)
