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Softa [21]
3 years ago
8

Which compound is composed of oppositely charged ions? A. OCl2 B. Na2O C. NH3 D. SCl2

Chemistry
2 answers:
Roman55 [17]3 years ago
6 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Compound having oppositely charged ions are considered as ionic compounds.

Ionic compounds are formed when complete transfer of electrons takes place between the atoms forming a bond. This bond is formed between a metal and a non-metal or a polyatomic cation and an non-metal or a metal and a polyatomic anion. <u>For Example:</u> NaCl,NH_4Cl,BaSO_4 etc..

Covalent compounds are formed when sharing of electrons takes place between the atoms forming a bond. This bond is formed between two non-metals. <u>For Example:</u> H_2O,SO_2 etc..

For the given options:

<u>Option A:</u>  OCl_2

Oxygen and chlorine both are non-metals. Thus, it is forming a covalent compound.

<u>Option B:</u>  Na_2O

Sodium is a metal and oxygen is a non-metal. Thus, it is forming an ionic compound and contain oppositely charged ions.

<u>Option C:</u>  NH_3

Nitrogen and hydrogen both are non-metals. Thus, it is forming a covalent compound.

<u>Option D:</u>  SCl_2

Sulfur and chlorine both are non-metals. Thus, it is forming a covalent compound.

Hence, the correct answer is Option B.

vazorg [7]3 years ago
5 0
It would be B, so yeah hope that helps ya ;)

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Answer:

The volume will be 0.031 L

Explanation:

Since temperature is constant, Boyle's law is applied in this case.

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From this statement it was deduced that P1V1 = P2V2

From the question, P1 = 1atm, V1 = 1.55L, P2 = 50 atm and V2 is to be calculated.

V2 = P1V1/P2

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5 0
3 years ago
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Olenka [21]
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5 0
3 years ago
Imagine you had HCl with a concentration of exactly 0.10 mol/dm3. If 0.023 dm3 of a sodium hydroxide solution, NaOH (aq), could
polet [3.4K]

Answer:

Explanation:

Step 1: Calculate the amount of sodium hydroxide in moles

Volume of sodium hydroxide solution = 25.0 ÷ 1,000 = 0.0250 dm3

Rearrange:

Concentration in mol/dm3 =

Amount of solutein mol = concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide = 0.100 × 0.0250

= 0.00250 mol

Step 2: Find the amount of hydrochloric acid in moles

The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

So the mole ratio NaOH:HCl is 1:1

Therefore 0.00250 mol of NaOH reacts with 0.00250 mol of HCl

Step 3: Calculate the concentration of hydrochloric acid in mol/dm3

Volume of hydrochloric acid = 20.00 ÷ 1000 = 0.0200 dm3

Concentration in mol/dm3 =

Concentration in mol/dm3 =

= 0.125 mol/dm3

Step 4: Calculate the concentration of hydrochloric acid in g/dm3

Relative formula mass of HCl = 1 + 35.5 = 36.5

Mass = relative formula mass × amount

Mass of HCl = 36.5 × 0.125

= 4.56 g

So concentration = 4.56 g/dm3

8 0
2 years ago
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5 0
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