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olchik [2.2K]
3 years ago
12

A 0.7 ft diameter hole forms in a tank containing butane at 19 atmg and 76 degrees Fahrenheit. Determine the maximum possible ma

ss flow rate through this leak in lb m / min, if the external pressure is 1 atm.
Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

Q = 3,534.4 lbm/s = 212,062 lbm/min

Explanation:

Mass flowrate of discharge or leakage mass flowrate (Q) is given as

Q = AC₀√(2ρgP)

A = Cross sectional Area of leakage = (πD²/4) = (π×0.7²)/4

A = 0.385 ft²

C₀ = discharge coefficient = 0.98 (For maximum discharge flow rate, the flow is turbulent with discharge coefficient within 1% of 0.98)

ρ = density of butane at 76°F = 35.771 lbm/ft³

g = acceleration due to gravity = 32.2 lbm.ft/lbf.s²

P = Gauge Pressure in the tank = (absolute pressure) - (external pressure) = 19 - 1 = 18 atm = 38091.9 lbf/ft²

Q = AC₀√(2ρgP)

Q = (0.385)(0.98)√(2×35.771×32.2×38091.9)

Q = 3,534.4 lbm/s = 212,062 lbm/min

Hope this Helps!!!

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The answer is D. Lactic Acid Fermentation!
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3 years ago
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When the following equation is balanced with lowest whole-number coefficients, what is the coefficient for NO(g)? ___NH3(g) + __
inn [45]

Answer:

Coefficient in front of the NO in the balanced equation - 4

Explanation:

The unbalanced reaction is shown below as:-

NH_3+O_2\rightarrow NO+H_2O

On the left hand side,  

There are 1 nitrogen atom and 3 hydrogen atoms and 3 oxygen atoms

On the right hand side,  

There are 1 nitrogen atom and 2 hydrogen atoms and 2 oxygen atoms

Thus,  

Right side, H_2O must be multiplied by 6 and NO by 4

Left side, O_2 is multiplied by 5 and NH_3 by 4 so to balance the whole reaction.

Thus, the balanced reaction is:-

4NH_3+5O_2\rightarrow 4NO+6H_2O

<u>Coefficient in front of the NO in the balanced equation - 4</u>

5 0
3 years ago
Lauryl alcohol is obtained from cocon ut oil and is used to make detergents. A solution of 5.00 g of lauryl alcohol in 0.100 kg
Len [333]

Answer:

185.2 g/mol.

Explanation:

Solvent = Benzene

Solute = lauryl alcohol

Given:

Mass of solute = 5 g

Mass of solvent = 0.1 kg

Freezing point of solvent, Temp.f = 4.1 °C

Initial freezing point of solvent, Temp.i = 5.5 °C

Molal freezing depression constant for Benzene, kf = 5.12 °C/m

ΔTemp.f = Temp.f - Temp.i

= 5.5 - 4.1

= 1.4 °C

ΔTemp.f = kf * m

Where m = molality

m = 1.4/5.12

= 0.27 mol/kg

Molality = number of moles of solute/mass of solvent

Number of moles = 0.27/0.1

= 0.027 mol.

Molar mass = mass/number of moles

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= 185.2 g/mol.

3 0
3 years ago
The balanced equation for the aerobic reaction is:
Furkat [3]

Answer:

1.85 g of hydrogen gas will form!

Explanation:

1. Write the balanced equation.

Zn

+

2HCl

→

ZnCl

2

+

H

2

2. Calculate the moles of

Zn

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Moles of Zn

=

30.0

g Zn

×

1 mol Zn

65.38

g Zn

=

0.4589 mol Zn

3. Calculate the moles of

H

2

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Moles of H

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=

0.4589

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2

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0.9177 mol H

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4. Calculate the mass of

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6 0
3 years ago
Write the step by step process of digestion in ruminants using 4 square method.
Vaselesa [24]

The digestion process in Ruminants begins by chewing and swallowing their food.

<h3>What are ruminants?</h3>

A ruminant is any herbivorous animal that has a stomach with four compartments, which are tasked with acquiring nutrients from plant-based food by fermenting it prior to digestion.

The digestion process in Ruminants begins by chewing and swallowing their food. Ruminants do not completely chew the food they eat, but just consume or gulp as much they can and then swallow the food. This is actually an adaptation by which these animals have evolved to spend as little time as possible feeding so that they are not hunted down by any predators while they are eating.

As mentioned earlier, the stomach of these Ruminants is divided into 4 chambers – rumen, reticulum, omasum, and the abomasum.

The process of digestion begins with the first two chambers of the stomach, the rumen and reticulum by softening the ingested matter. Later the microbes present in the rumen produces the cellulase enzymes required to digest the cellulose.

Once the plant fibres have been broken down to provide vitamins, proteins, and other organic acids, the nutrients are absorbed into the animal’s bloodstream.

Coarse plants are sent further into the next chamber for further digestion. Here is where the further bacterial action takes place and the food is formed into soft chunks called the cud.

This cud produced is regurgitated back into the animal’s mouth where it can be chewed again. The saliva of the cow greatly aids in digesting the cud.

After chewing, the food bypasses the two chambers of the stomach and directly enters the third chamber. The walls of the third chamber mash and compact the food molecules further, and then pass it to the fourth chamber – the abomasum.

The final digestion in the stomach is carried by the abomasum and then passed to the intestine.

Learn more about the ruminants here:

brainly.com/question/26752412

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3 0
2 years ago
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