Answer:
Q = 3,534.4 lbm/s = 212,062 lbm/min
Explanation:
Mass flowrate of discharge or leakage mass flowrate (Q) is given as
Q = AC₀√(2ρgP)
A = Cross sectional Area of leakage = (πD²/4) = (π×0.7²)/4
A = 0.385 ft²
C₀ = discharge coefficient = 0.98 (For maximum discharge flow rate, the flow is turbulent with discharge coefficient within 1% of 0.98)
ρ = density of butane at 76°F = 35.771 lbm/ft³
g = acceleration due to gravity = 32.2 lbm.ft/lbf.s²
P = Gauge Pressure in the tank = (absolute pressure) - (external pressure) = 19 - 1 = 18 atm = 38091.9 lbf/ft²
Q = AC₀√(2ρgP)
Q = (0.385)(0.98)√(2×35.771×32.2×38091.9)
Q = 3,534.4 lbm/s = 212,062 lbm/min
Hope this Helps!!!
