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Dmitriy789 [7]
3 years ago
11

I do not understand this! please help!

Mathematics
1 answer:
Bad White [126]3 years ago
7 0

Answer:

So this is an algebra question, yes?

So an equation of a line follows this format: y=mx+b.

(m is your slope. b is the y-int)

In order to get to that equation, you use the formula: y-y¹=m(x-x¹).

(this is your point-slope formula)

If you are given two points, they want you to use this formula to find the slope:

y²-y¹ all divided by x²-x¹. (Fraction form).

so, label the points.

(0,6) 0 will be x¹. 6 will be y¹.

(3,0) 3 will be x².. 0 will be y².

(0-6) all over (3-0).

you get -6 over 3. You can simplify that to -2.

-2 is your slope.

so plug that into the second formula along with either one of the points given to you. I am going to choose (0,6) randomly.

y-6=-2(x-0)

Then you solve like a regular equation.

y-6=-2x. [-2×0 is 0 so dont include it]

y=-2x+6 [bring the -6 over by adding it]

There is your equation of the line that passes through both of those points.

Slope intercept form is the equation that has both the slope (-2) and the y intercept (6).

Point-slope form is the long formula we used to get the slope intercept form. It is called that because it shows a point on the graph (0,6) and the slope (-2).

Normally, they will ask you for the slope-intercept form.

Hope this helps.

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MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

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Hey!

-------------------------------------

Solution:

Divide to get the decimal.

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Answer:

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