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Andrej [43]
3 years ago
11

If I have 28 sixth graders and 35 seventh graders how many groups can I have with none leftover

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0
Find GCF of 28 and 35:-

28 = 4*8
35 = 5*7     so GCF is 7

So you can have  7 groups of  4 6th graders with 5 7th graders

That is  7 groups  of 9  with none left over.

Answer is 7 groups.


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3 0
3 years ago
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You roll two standard number cubes. What is the probability that the sum is odd, given than one of the number cubes shows a 1?
Virty [35]
 It's not specified whether 1 is the 1st or 2nd roll: HOWER:

The 1st Roll is "1": P(odd sum/the 1st Roll is 1)
What is the sample space of all numbers starting with "1":
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the couple of add sum=(1,2), (1,4), (1,6), =3
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or in applying the formula:

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6 0
3 years ago
Casey wants to buy a gym membership. One gym has a $176 joining fee and costs $29 per month. Another gym has no joining fee and
kaheart [24]

Answer:

8 months for cost to be same, cost will be $408

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x = months

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3 0
3 years ago
Which table of values corresponds to the graph below?
Lelechka [254]
Here you go hope this helps

3 0
2 years ago
How do I solve this
Sladkaya [172]

Step-by-step explanation:

\bf \underline{Solution-} \\

\textsf{Given,}\\

\sf{ \frac{ {a}^{6} {b}^{4}  }{ {a}^{2} {b}^{3}  } } \\

\textsf{Using law of intergal expo.. aᵐ ÷ aⁿ = aᵐ - ⁿ}\\

\sf{ \Rightarrow \:  {a}^{(6 - 2)}  {b}^{(4 - 3)} } \\

\sf{ \Rightarrow \:  {a}^{4}  {b}^{1} } \\

\sf{ \Rightarrow \:  {a}^{4}  {b}^{} } \\

\bf \underline{Hope\: this\: helps.} \\

4 0
2 years ago
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