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Andrej [43]
3 years ago
11

If I have 28 sixth graders and 35 seventh graders how many groups can I have with none leftover

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0
Find GCF of 28 and 35:-

28 = 4*8
35 = 5*7     so GCF is 7

So you can have  7 groups of  4 6th graders with 5 7th graders

That is  7 groups  of 9  with none left over.

Answer is 7 groups.


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I need help with this problem I didn't really pay that much attention to this part of the subject.​
Flauer [41]

To check if a piecewise defined function is continuous, you need to check how the pieces "glue" together when you step from one domain to the other.

So, the question is: what happens at x=3? If you reach x=3 from values slightly smaller than 3, you obey the rule f(x)=log(3x). So, as you approach 3, you get values closer and closer to

\log(3\cdot 3)=\log(9)

Similarly, if you reach x=3 from values slightly greater than 3, you obey the rule f(x)=(4-x)log(9). So, as you approach 3, you get values closer and closer to

(4-3)\log(9)=\log(9)

So, the function is continuous at x=3, because both pieces approach log(9) as x approaches 3.

4 0
3 years ago
What’s the answer guys .
UNO [17]

Answer:

Hello! Your answer would be, D)

Step-by-step explanation:

Hope I helped! Ask me anything if you have more questions! Brainiest plz Have a nice mourning! Hope you make an 100%! -Amelia♥

4 0
3 years ago
Rewrite using the Associative Property, then evaluate. 10 x (3 x 14) & (12 + 21) + 34
Eduardwww [97]
10 times (3*4)
You have to multiply 10 with both of the numbers in parenthesis
So, 10*3=30 and 10*4=40
30+40=70
Does this look right for the first one

5 0
3 years ago
olivia divided a fraction by 3\4 the quotient was a whole number was the divident less than 3\4? explain
svp [43]

Good evening ,

______

Answer:

No

___________________

Step-by-step explanation:

Look at the photo below for the details.

:)

4 0
3 years ago
Read 2 more answers
If CE=7 in and AE=23 in AC=
dusya [7]
I think it = 16 but then again I could be wrong
3 0
3 years ago
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