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3 years ago

6

A basketball player can leap upward 0.43 m. how long does he remain in the air? use an acceleration due to gravity of 9.80 m/s2

and find your answer to the nearest 0.001 s.

1 answer:

MArishka [77]3 years ago

3 0

From the equations of linear motion,
v² = u² + 2as where v is the final velocity, u is the initial velocity and a is the gravitational acceleration, and s is the displacement,
Thus, v² = u² -2gs, but v=0
hence, u² = 2gs
= 2×9.81×0.43
= 8.4366
u = √8.4366
=2.905 m/s
Hence the initial velocity is 2.905 m/s
Then using the equation v= u +gt .
Therefore, v = u -gt. (-g because the player is jumping against the gravity)
but, v = 0
Thus, u= gt
Hence, t = u/g
= 2.905/9.81
= 0.296 seconds

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The behavior of infrared, ultraviolet, and visible light is explained by the science of optics. Ray is the name given to the route that light takes. A beam of light is another name for a collection of light rays.

To view more on the Ray Optics and Optical Instrument, refer to:

brainly.com/question/19866597

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