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Lunna [17]
3 years ago
8

7. How do Newton’s laws of motion explain why it is important to keep the ice smooth on a hockey rink so that players can pass a

puck as quickly as possible? *
Physics
2 answers:
Viktor [21]3 years ago
8 0

Answer:

Smooth ice reduces the unbalanced forces that would slow the hockey puck.

(The answer is c.)

Explanation

i  jus took the quiz :(

Arisa [49]3 years ago
5 0
The first law states that “objects at rest and objects in motion remain in motion in a straight line unless acted upon by an unbalanced force”. Keeping the ice smooth will make sure there is not friction, friction would slow the puck down
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Which correctly describes electric potential, electric field, and electric (or electrostatic) force?
vlabodo [156]

Answer:

E

Explanation:

A vector is a physical quantity that has magnitude and direction while a scalar is a physical quantity that has magnitude only

*electric potential is a scalar quantity because it only has magnitude

*electric field and electric force are vector quantities because they have magnitude and direction

7 0
3 years ago
The position of a particle moving along the x-axis depends on the time according to the equation x = ct2 - bt3, where x is in me
Sav [38]

Answer:

(a):  \rm meter/ second^2.

(b):  \rm meter/ second^3.

(c):  \rm 2ct-3bt^2.

(d):  \rm 2c-6bt.

(e):  \rm t=\dfrac{2c}{3b}.

Explanation:

Given, the position of the particle along the x axis is

\rm x=ct^2-bt^3.

The units of terms \rm ct^2 and \rm bt^3 should also be same as that of x, i.e., meters.

The unit of t is seconds.

(a):

Unit of \rm ct^2=meter

Therefore, unit of \rm c= meter/ second^2.

(b):

Unit of \rm bt^3=meter

Therefore, unit of \rm b= meter/ second^3.

(c):

The velocity v and the position x of a particle are related as

\rm v=\dfrac{dx}{dt}\\=\dfrac{d}{dx}(ct^2-bt^3)\\=2ct-3bt^2.

(d):

The acceleration a and the velocity v of the particle is related as

\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(2ct-3bt^2)\\=2c-6bt.

(e):

The particle attains maximum x at, let's say, \rm t_o, when the following two conditions are fulfilled:

  1. \rm \left (\dfrac{dx}{dt}\right )_{t=t_o}=0.
  2. \rm \left ( \dfrac{d^2x}{dt^2}\right )_{t=t_o}

Applying both these conditions,

\rm \left ( \dfrac{dx}{dt}\right )_{t=t_o}=0\\2ct_o-3bt_o^2=0\\t_o(2c-3bt_o)=0\\t_o=0\ \ \ \ \ or\ \ \ \ \ 2c=3bt_o\Rightarrow t_o = \dfrac{2c}{3b}.

For \rm t_o = 0,

\rm \left ( \dfrac{d^2x}{dt^2}\right )_{t=t_o}=2c-6bt_o = 2c-6\cdot 0=2c

Since, c is a positive constant therefore, for \rm t_o = 0,

\rm \left ( \dfrac{d^2x}{dt^2}\right )_{t=t_o}>0

Thus, particle does not reach its maximum value at \rm t = 0\ s.

For \rm t_o = \dfrac{2c}{3b},

\rm \left ( \dfrac{d^2x}{dt^2}\right )_{t=t_o}=2c-6bt_o = 2c-6b\cdot \dfrac{2c}{3b}=2c-4c=-2c.

Here,

\rm \left ( \dfrac{d^2x}{dt^2}\right )_{t=t_o}

Thus, the particle reach its maximum x value at time \rm t_o = \dfrac{2c}{3b}.

7 0
3 years ago
Which of the following is an example of adhesion?
nalin [4]
What are the answers?
3 0
3 years ago
The ____ is a measure of the number of waves that pass a point in a given amount of time
nikitadnepr [17]

The (frequency of the wave multiplied by the number of seconds
in a given amount of time)
is the measure of the number of waves that
pass a point in that amount of time.

If you had said "in one second" instead of "in a given amount of time,
then the word in the blank would simply be frequency.
8 0
3 years ago
Read 2 more answers
How long does it take to walk 2000 miles?
adoni [48]

The average human walking speed at crosswalks is about about 3.1 miles per hour (mph) or 5.0 kilometers per hour (km/h).

In order to calculate the time needed to walk 2000 miles, we should divide 2000 with the average speed.

2000 miles / 3.1 miles per hour= 645,161 hours

It takes 645 hours to walk 2000 miles.

4 0
4 years ago
Read 2 more answers
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