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2 years ago

What is the distance of KF. round to the nearest tenths

Mathematics

1 answer:

snow_tiger [21]2 years ago

5 0

Answer:

its 9.2

Step-by-step explanation:

Well i counted 7 units (x-axis) and 6 units (y axis). 6 squared is 36 and 7 squared is 49. Add them together and get 85. Square root 85 and youll get 9.21954445729. Round it to the nearest tenths and get 9.2

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Zielflug [23.3K]

Answer: 12

Step-by-step explanation:

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3 years ago

Match each value with its formula for ABC.

MariettaO [177]

The solution to the question is:

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

<h3>What is cosine rule?</h3>

it is used to relate the three sides of a triangle with the angle facing one of its sides.

The square of the side facing the included angle is equal to the some of the squares of the other sides and the product of twice the other two sides and the cosine of the included angle.

Analysis:

If c is the side facing the included angle C, then

$c^{2}$ = $a^{2}$ + $b^{2}$ -2ab cos C-----------------1

then c = $\sqrt{a^{2} + b^{2} -2abcosC }$

if b is the side facing the included angle B, then

$b^{2}$ = $a^{2}$ + $c^{2}$ -2accosB-----------------2

b = $\sqrt{a^{2} + c^{2} -2accosB }$

from equation 2, make cosB the subject of equation

2ac cosB = $a^{2}$ + $c^{2}$ - $b^{2}$

cosB = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

if a is the side facing the included angle A, then

$a^{2}$ = $b^{2}$ + $c^{2}$ -2bccosA--------------------3

a = $\sqrt{b^{2} + c^{2} -2bccosA }$

from equation 3, making cosA subject of the equation

2bcosA = $b^{2}$ + $c^{2}$ - $a^{2}$

cosA = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

from equation 1, making cos C the subject

2abcosC = $b^{2}$ + $a^{2}$ - $c^{2}$

cos C = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

In conclusion,

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

Learn more about cosine rule: brainly.com/question/4372174

$SPJ1

4 0

2 years ago

Find an equation of the line L that passes through the point (−2, 9) and satisfies the condition. L is perpendicular to the line

castortr0y [4]

This picture explained answer thanks

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3 years ago

The speeds in miles per hour of seven randomly selected qualifiers for the Indianapolis 500 (in 2012) are listed below. Estimate

SSSSS [86.1K]

Answer:

Mean qualifying speed

= 224.5669mi/hr

Speed that passed the average/mean

= 226.240mi/hr ,224.037mi/hr 226.484mi/hr, 225.172 mi/hr

Step-by-step explanation:

Let's understand what mean is then understand what mean qualifying speed is.

First mean is like the average of the seven speed listed below.

So let's find the mean.

Mean = (223.684+ 222.929+ 226.240

+224.037 +226.484+ 225.172

+223.422)/7

Mean = 1571.968/7

Mean = 224.5669

So the mean qualifying speed is those speed that qualifies when the mean is taken, i.e the speed that crossed the average.

Mean qualifying speed are

=226.240 ,224.037,226.484

, 225.172

4 0

3 years ago

A cupcake is 3 inches wide , 3 inches long , 3 inches high . How many cupcakes will fit in a box measuring 15 inches high , 7 cm

Volgvan

Answer:

23 cupcakes

Step-by-step explanation:

Volume is the key to this question;

Calculate the volume of the cupcake;

3 × 3 × 3 = 27 inches^3

Then the volume of the box;

15 × 7 × 6 = 630 inches^3

Then divide the volume of the box by the volume of the cupcake to see how many can fit in;

630 ÷ 27 = 23.3333

;Hence you can fit... 23 cupcakes

3 0

3 years ago

What is the distance of KF. round to the nearest tenths ​

What is the distance of KF. round to the nearest tenths