Answer:
s≥16
Step-by-step explanation:
3s+52≥100
3s≥100-52
3s≥48
s≥48/3
s≥16
To find the answer set up an equation:

Using this set up we can cross our units of pages since they are on opposite side of the proportion, leaving us with the desired units of hours.
Then divide 400 by 65 which will give us our answer: 6.15 or about 6 hours for Jamie to finish her reading.
Answer:
B and C are correct
Step-by-step explanation:
17/4 = 4.25
4 and 1/4 = 17/4
Answer:
See below
Step-by-step explanation:
The purpose of the confidence interval is to give a range of where the true value of a parameter lies given a confidence level.
Question:
If cos(θ) =-8/17 and sin(θ) is negative, then sin(θ) = ___ and tan(θ) =___.
Answer:


Step-by-step explanation:
Given
cos(θ) =-8/17
Required
sin(θ) = __
tan(θ) =__
The first step is to determine the length of the third side
Given that

Where Adj and Hyp represent Adjacent and Hypotenuse

By comparison

Using Pythagoras

By Substitution


Subtract 64 from both sides


Take square roots of both sides




The question says that sin(θ) is negative; This implies that θ is in the third quadrant and as such

From trigonometry


Also from trigonometry





