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Firdavs [7]
3 years ago
7

I also bought $7$ different postcards. How many ways can I send the postcards to my $3$ friends, so that each friend gets at lea

st one postcard?
How do i count the restriction that each friend must get at least 1 or more postcards and the postcards are distinguishable?
Mathematics
1 answer:
harina [27]3 years ago
5 0
Bruh how’s it gonna tell me incorrect answer when it was right
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The outer tire radius of Jasmine's bike wheel is approximately 14 inches. How far will her wheel travel in three revolutions? Gi
Brrunno [24]
I have found that 34inches
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3 years ago
A tank full of water is leaking at a constant rate for 30 minutes. The equation
ankoles [38]

Answer:  A. There were 500 liters in the tank when the leak started, and it is  decreasing by 9 liters per minute.

Step-by-step explanation:

This equation is in the form; y =mx + c.

<em>c</em> in this equation is the value of y when x is at 0.

<em>c</em> in the above formula is 500 which means that the number of litres (y) at zero minutes(x) is 500 litres.

<em>m</em> is the rate of change as a result of a change in x.

<em>m</em> in this equation is -9 which means that the water is reducing by 9 litres every minute (x).

3 0
3 years ago
The slope of (- 7,9) and (6,- 5)
kaheart [24]
\bf{Slope = \frac{y_2-y_1}{x_2-x_1}  =\frac{9 - (-5)}{-7-6} =\frac{14}{-13}}\\\\\boxed{\bf{\Large Slope = -\frac{14}{13}}}
3 0
3 years ago
What is the equation of this line?
quester [9]

A. y = 2x - 3

This is the correct answer

4 0
3 years ago
Abdul, while driving to school, computes the average speed for his trip to be 20 km/hr. On his return trip along the same route,
gulaghasi [49]
You need to find the total distance and the total time. The total distance is two times the distance to school, 2d.s=d/t=>t=d/sWhere s is speed, d is distance and t is time. So the time taken to get to school is:d/s1and the time taken to get back is:d/s2so the total time is:d/s1+d/s2=d(1/s1+1/s2)So, as speed = distance/time, divide the total distance by the total time:2d/d(1/s1+1/s2)=2/(1/s1+1/s2)=2/(1/20+1/40)=80/3≈26.7km/hr
8 0
3 years ago
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