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Firdavs [7]
3 years ago
7

I also bought $7$ different postcards. How many ways can I send the postcards to my $3$ friends, so that each friend gets at lea

st one postcard?
How do i count the restriction that each friend must get at least 1 or more postcards and the postcards are distinguishable?
Mathematics
1 answer:
harina [27]3 years ago
5 0
Bruh how’s it gonna tell me incorrect answer when it was right
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Can you help me solve this radical equation √y-10 = y-2 the sqrt sign is only over the y-10
matrenka [14]
D:y-10\geq0 \wedge y-2\geq0\\
D:y\geq10 \wedge y\geq2\\
D:y\geq10\\\\
\sqrt{y-10}=y-2\\
y-10=(y-2)^2\\
y-10=y^2-4y+4\\
y^2-5y+14=0\\
\Delta=(-5)^2-4\cdot1\cdot14=25-56=-31\\
\Delta
7 0
3 years ago
a pie chart is divided into four sectors in fig. 12.42. Each sector represents a percentage of the whole. The two larger sectors
Novosadov [1.4K]

Answer:

Angle formed by the sector measuring x% will be 126°.

Step-by-step explanation:

Since, sum of all sectors formed in a circle is 100%.

By adding the measures of all the sectors,

x + x + 21 + 9 = 100

2x + 30 = 100

2x = 70

x = 35%

Now we know sum of all the central angles formed at the center of a circle = 360°

Therefore, angle formed by x% = 360° × 35%

                                                    = \frac{360\times 35}{100}

                                                    = 126°

8 0
3 years ago
Does anyone know this?
lana66690 [7]

Answer:

Δ HGI ≅ ΔEDF

Step-by-step explanation:

Given:

Δ DEF ≅ Δ GHI

From the given congruence statement we can figure out the corresponding sides that are congruent.

The arrangement shows:

D\rightarrow G\\E\rightarrow H\\F\rightarrow I

So the rearranged statement can be written as:

ΔEDF ≅ Δ HGI

or

∴ Δ HGI ≅ ΔEDF

8 0
3 years ago
Resolver usando recíprocos y multiplicativo inverso: 2X-8 = 2 5<br>​
STatiana [176]

2x - 8 = 25

2x = 25 - 8

x = 17 \div 2

x = 8.5

7 0
2 years ago
Greatest common factor of 4ax^2+4ax+4a
Rina8888 [55]

Simplifying

4AX2 + 4AX + 4A = 0

Reorder the terms:

4A + 4AX + 4AX2 = 0

Solving

4A + 4AX + 4AX2 = 0

Solving for variable 'A'.

Move all terms containing A to the left, all other terms to the right.

Factor out the Greatest Common Factor (GCF), '4A'.

4A(1 + X + X2) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'A' equal to zero and attempt to solve:

Simplifying

A = 0

Solving

A = 0

Move all terms containing A to the left, all other terms to the right.

Simplifying

A = 0

Subproblem 2

Set the factor '(1 + X + X2)' equal to zero and attempt to solve:

Simplifying

1 + X + X2 = 0

Solving

1 + X + X2 = 0

Move all terms containing A to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + X + -1 + X2 = 0 + -1

Reorder the terms:

1 + -1 + X + X2 = 0 + -1

Combine like terms: 1 + -1 = 0

0 + X + X2 = 0 + -1

X + X2 = 0 + -1

Combine like terms: 0 + -1 = -1

X + X2 = -1

Add '-1X' to each side of the equation.

X + -1X + X2 = -1 + -1X

Combine like terms: X + -1X = 0

0 + X2 = -1 + -1X

X2 = -1 + -1X

Add '-1X2' to each side of the equation.

X2 + -1X2 = -1 + -1X + -1X2

Combine like terms: X2 + -1X2 = 0

0 = -1 + -1X + -1X2

Simplifying

0 = -1 + -1X + -1X2

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

Solution

A = {0}

3 0
3 years ago
Read 2 more answers
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