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Firdavs [7]
3 years ago
7

I also bought $7$ different postcards. How many ways can I send the postcards to my $3$ friends, so that each friend gets at lea

st one postcard?
How do i count the restriction that each friend must get at least 1 or more postcards and the postcards are distinguishable?
Mathematics
1 answer:
harina [27]3 years ago
5 0
Bruh how’s it gonna tell me incorrect answer when it was right
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Erik buys 2.5 pounds of cashews. If each pound of cashews costs $7.70, how much will he pay for the cashews?
Liula [17]

Answer:

$19.25

Step-by-step explanation:

2.5*7.7=19.25

6 0
3 years ago
Read 2 more answers
The sum of the tens digit and the hundreds digit of a number is three times the units digit. 1/5 of the sum of all three digits
Crazy boy [7]

Answer: The numbers are:

965

875

785

695

Step-by-step explanation:

We have a 3 digit number that can be written as:

a*100 + b*10 + c

Where a, b, and c are single-digit numbers.

a is the hundreds

b is the tens

c is the unit.

We know that:

"The sum of the tens digit and the hundreds digit of a number is three times the units digit."

a + b = 3*c

" 1/5 of the sum of all three digits is 1 less than the units digit."

(a + b + c)/5 = c - 1

Then we have the two conditions:

a + b = 3*c

(a + b + c)/5 = c - 1

From the first one, we can write:

(a + b)/3 = c

Replacing that in the other equation we get:

(a + b + a/3 + b/3)/5 = a/3 + b/3 - 1

(4/3)*(a + b)/5 = (a/3 + b/3) - 1

(4/15)*(a + b) = (a + b)/3 - 1

(4/15)*(a + b) - (a + b)/3 = - 1

-(1/15)*(a + b) = -1

a  = 15 - b

Then we can give different values for b, and find the values of a and c, where a and c must be positive.

b = 9

a = 15 - 9 = 6

Then:

c = (9 + 6)/3 = 5

(notice that a + b = 15, then c will be always equal to 5, reggardless of the values of b and a).

This number will be:

695.

if b = 8, then:

a = 15 - 8 = 7

and c = 5, same as before.

the number is 785.

If b = 7, then:

a = 15 - 7 = 8

The number is 875

if b = 6, then:

a = 15 - 6 = 9

The number is:

965

4 0
3 years ago
Suppose that a box contains 7 cameras and that 5 of them are defective. A sample of 2 cameras is selected at random without repl
irinina [24]

Answer:

E(x) = 1.43 (Approx)

Step-by-step explanation:

Given:

Total number of camera = 7

Defective camera = 5

Sample selected = 2

Computation:

when x = 0

P(x=0) = 2/7 × 1/6 = 2/42

P(x=1) = [2/7 × 5/6] + [5/7 × 2/6] = 20/42

P(x=2) = 5/7 × 4/6 = 20/42

So,

E(x) = [0×2/42] + [1×20/42] + [2×20/42]

E(x) = 1.43 (Approx)

8 0
3 years ago
(2 tens 1 one)x10 in unit form and standard form
omeli [17]

When the number expression given as (2tens 1 one) x 10 is written in standard form, the standard form is 210 and the unit form is 2 hundred, and 1 ten

<h3>How to write the number in standard form?</h3>

The number expression is given as:

(2tens 1 one) x 10

2 tens is represented as:

2 * 10

1 one is represented as:

1 * 1

So, the number expression can be rewritten as:

(2tens 1 one) x 10 = (2 * 10 + 1 * 1) x 10

Evaluate the product

(2tens 1 one) x 10 = (20 + 1) x 10

Evaluate the sum

(2tens 1 one) x 10 = (21) x 10

Evaluate the product

(2tens 1 one) x 10 = 210

When the number expression given as (2tens 1 one) x 10 is written in standard form, the standard form is 210 and the unit form is 2 hundred, and 1 ten

Using the above steps as a guide, we have:

  • (5 hundreds 5 tens) * 10 ⇒ 5 thousands and 5 hundreds ⇒ 5500
  • (2 thousands 7 tens) / 10 ⇒ 2 hundreds and 7 units ⇒ 207
  • (4 ten thousands 8 hundred) / 10 ⇒ 4 thousands and 8 tens ⇒ 4080

Read more about standard form at

brainly.com/question/19169731

#SPJ1

4 0
2 years ago
What is payday on the 1st and 15th referred as (2 times a month)? *
Gnoma [55]

Answer:

b, semi-monthly

6 0
3 years ago
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