Ask question

Ask question

All categories

3 years ago

7

I also bought $7$ different postcards. How many ways can I send the postcards to my $3$ friends, so that each friend gets at lea

st one postcard?
How do i count the restriction that each friend must get at least 1 or more postcards and the postcards are distinguishable?

1 answer:

harina [27]3 years ago

5 0

Bruh how’s it gonna tell me incorrect answer when it was right

You might be interested in

Each set of directions describes how to plot a point starting at the origin.

Sergio039 [100]

Answer:

right 6

down 1

(6,-1)

up 6

left 1

(-1,6)

right 1

down 6

(1,-6)

down 6

right 1

(1,-6)

left 1

up 6

(-1,6)

4 0

3 years ago

Read 2 more answers

Choose the table that represents g(x) = −2⋅f(x) when f(x) = x + 4

fomenos

Answer:

x g(x)

1 −10

2 −12

3 −14

Step-by-step explanation:

Substitute the values and do the arithmetic.

Table values for x are 1, 2, 3. We only need to find g(1) to determine which table is the correct choice.

f(1) = 1 +4 = 5 . . . . . . . . . put 1 where x is and do the arithmetic

g(1) = -2·f(1) = -2·5 = -10 . . . . . matches the 3rd choice

6 0

3 years ago

Find the measure of angle 1

kaheart [24]

Answer:

112*

Step-by-step explanation:

( 360 - 46 - 90 ) ÷ 2 = 112

8 0

2 years ago

Please help me find the median!

musickatia [10]

The median for this set of data, I believe it is Team Leader. Mostly because the middle wage is Team Leader, along with the wage.

7 0

3 years ago

Find the diameter(s) of circle O.

schepotkina [342]

Answer:

The diameter of the circle O is <em>12 units</em>

Step-by-step explanation:

There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of

$BC=6\sqrt{2}$

and the triangle B0C is right

<u>Relations in the Circle</u>

The diameter (D) is twice the radius (r) and the radius is the distance measured from the center of the circle to any point of the circumference.

Since the triangle B0C has a right angle, BD is the hypotenuse and 0B=0C=r

Applying Pythagoras's theorem:

$BC^2=r^2+r^2=2r^2$

Thus we have

$2r^2=(6\sqrt{2})^2$

$2r^2=72$

$r^2=36$

$r=6$

The diameter of the circle O is D=2(6) = 12 units

5 0

3 years ago