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3 years ago

Which angles are complementary to

Mathematics

1 answer:

Molodets [167]3 years ago

8 0

Complementary angles add up to 90°

∠BDC + ∠CDA = 90°

Answer: ∠BDC

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(12, 9, 4) What is the area of the parallelogram shown below?

zavuch27 [327]

area of the parallelogram is: b x h

12 x 4 = 48 (d)

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3 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

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3 years ago

AB formed by (-8, -1) and (-4, 2)<br> CD formed by (0, -3) and (12, 6)

marysya [2.9K]

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3 years ago

A cylinder has a height of 12cm.

stich3 [128]

Answer:

the answer for your question is 1200pi

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2 years ago

Find the value of x, y, and z.

horsena [70]

X= 45
z=45
y=90
180-135 is 45 degrees for Z. X is also 45 while y then becomes 90. as 90+45+45=180.

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3 years ago