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3 years ago

Find the vertices and foci of the hyperbola with equation (x-3)^2/16-(y+4)^2/9 = 1

Mathematics

1 answer:

ladessa [460]3 years ago

6 0

Answer:well first you should start with the problem (x-3)^2/16-(y+4)^2/9=1

Then solve it and you should get the answer

Hope this helps!

Step-by-step explanation:

You might be interested in

How does the division rule for exponents help in understanding why anything to the zero power is 1?

Nookie1986 [14]

In the division rule you subtract the exponents when dividing numbers with the same base. One rule for exponents is that exponents add when you have the same base. This works for any number x that you want to plug in except for x = 0,because 0/0 is indeterminate (it is like dividing zero by zero). No matter what number we use when it is raised to the zero power it will always be 1.

5 0

3 years ago

Is matrix multiplication comutative?

konstantin123 [22]

Answer:

Matrix multiplication is not conmutative

Step-by-step explanation:

The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix

Let A with dimension mxn and B with dimension nxp represent two matrix

The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.

But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.

The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:

$A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]$

Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.

6 0

3 years ago

Please help me now. Needs to be done soon.

Likurg_2 [28]

Hey There!

your win/lose ratio is 5/6 and you have 10 on your first one 5×2=10 so 6×2=12
the other one you have 18 so 6×3=18 so, 5×3=15 thus these being your answers.

Hope This Helps!!!

8 0

3 years ago

Read 2 more answers

Solve and check thanks

navik [9.2K]

The solution is x=-1

6 0

3 years ago

HELP PLEASE! PRE-ALGEBRA!

serious [3.7K]

Answer:

Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 2. and then rotating it about the origin by 180 degrees

Step-by-step explanation:

Step 1: Dilation by a scale factor of 1/2.

A point (x, y) is sent to (1/2 x, 1/2 y).

A(2, 2) ---> (1, 1)

B(2, 10) ---> (1, 5)

C(8, 12) ---> (4, 6)

Step 2: Rotate about the origin 180 degrees

A point (x, y) is sent to (-x, -y).

(1, 6) ---> A'(-1, -1)

(1, 5) ---> B'(-1, -5)

(4, 6) ---> C'(-4, -6)

6 0

3 years ago