Answer:
(x +3)^2 + (y -3)^2 = 3^2
Step-by-step explanation:
Your first task is to find the center.
The longest possible line of the circle goes from (-3,0) to (-3,6)
So the center is at the midpoint of these two points.
The midpoint is at (-3 - 3)/2 , (6+ 0)/2 or (-3,3)
That gives you the center of the circle.
So far what you have is
(x +3)^2 + (y -3)^2 = r^2
Now the distance of the center to the bottom point is (-3,3) to (-3,0)
r^2 = (x2 - x1)^2 + (y2 - y1)^2
x2 = - 3
x1 = - 3
y2 = 3
y1 = 0
r^2 = (-3 - -3)^2 + (3 - 0)^2
r^2 = 3^2
The entire answer is
(x +3)^2 + (y -3)^2 = 3^2
GiveN:
- ABCD is a parallelogram.
- AC and BD are the diagonals.
- DE = 28 units
To FinD:
- Value of x in length of BE?
Step-wise-Step Explanation:
We know that
In any parallelogram, the diagonals (lines linking opposite corners) bisect each other. Then, AE = EC for diagonal AC and BE = DE for diagonal BD.
⇒ BE = DE
⇒ x - 4 = 28 units
⇒ x = 32 units
Hence, The required value of x here is <u>3</u><u>2</u><u> </u><u>units</u><u>.</u>
For the answer to the question above,
<span>g(f(x)) = (4x^2 + x + 1)^2 - 2 </span>
<span>g(f(x)) = (16x^4 + 4x^3 + 4x^2 + 4x^3 + x^2 + x + 4x^2 + x + 1) - 2 </span>
<span>g(f(x)) = 16x^2 + 8x^3 + 9x^2 + 2x + 1 - 2 </span>
<span>g(f(x)) = 16x^2 + 8x^3 + 9x^2 + 2x - 1
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
Answer:
1/a^2 is the answer to this question
Let's find what 1/6 of an hour is.
1/6×60=10
So, ten minutes is equal to 1/6 of an hour. Let's find hour many sets of 10 minutes are in six hours. Let's first find the amount of minutes.
6×60=360
360÷10
36
Let's multiply that by 94.
94×36
3,384 miles in 6 hours.
