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Alecsey [184]
2 years ago
7

Lindsey found a cupcake and weighed it on a digital scale. The cupcake weight 0.35 lb. what is the weight of the Rock in expande

d form
Mathematics
1 answer:
SVEN [57.7K]2 years ago
7 0

The weight of the cupcake in an expanded form is 3.5 * 10⁻¹ lb

<h3>How to determine the weight?</h3>

The weight is given as:

Weight = 0.35 lb

Remove the unit

Weight = 0.35

Multiply the weight by 1

Weight = 0.35 * 1

Express 1 as 10/10

Weight = 0.35 * 10/10

Evaluate the product

Weight = 3.5 * 1/10

Express 1/10 as an exponent

Weight = 3.5 * 10⁻¹

Return the unit

Weight = 3.5 * 10⁻¹ lb

Hence, the weight in expanded form is 3.5 * 10⁻¹ lb

Read more about metric units at:

brainly.com/question/2555957

#SPJ1

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Yes, you are right. the length is 3, the height is 2, and the width is 1

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What is 5 2/7 rounded to the nearest whole number
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5 and 2/7 would be closer to the whole number 5 than 6

Your answer would be 5

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A person whose eye level is 20 feet above the ground is looking at a building. The angle of elevation to the top of the building
Inessa [10]
Distance of the person from the building (x)

tan 24 = 20/x => x = 20/tan 24 = 44.92 ft

The height of the building above the height of the person and the distance of the person from the building forms two legs of right angled triangle.

Therefore, if h is the height of the building, then;
tan 31 = (h-20)/44.92
h-20 = 44.92 tan 31
h = (44.92 tan 31) + 20 = 26.99 + 20 = 46.99 ft
8 0
2 years ago
The thickness of a plastic film (in mils) on a substrate material is thought to be influenced by the temperature at which the co
statuscvo [17]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if rising the process temperature reduces the thickness of the plastic film that coats a substrate material To do so, two samples of substrates are coated at different temperatures:

Sample 1

X₁: Thickness of the plastic film after the substrate is coated at 125F

n₁=11

X[bar]₁= 101.28

S₁= 5.08

Sample 2

X₂: Thickness of the plastic film after the substrate is coated at 150F

n₂= 13

X[bar]₂= 101.70

S₂= 20.15

Does the data support this claim? Use the P-value approach and assume that the two population standard deviations are not equal.

Now if the higher the heat, the thinner the thickness of the plastic coating, then the average thickness of the coating done at 150F should be less than the average thickness of the coating done at 125F, symbolically: μ₂ < μ₁

Then the hypotheses are:

H₀: μ₂ ≥ μ₁

H₁: μ₂ < μ₁

α:0.05 (there is no α level stated so I've chosen the most common one)

Assuming that both variables have a normal distribution since the population standard deviations are not equal, the statistic to use is the Welch's t-test:

t= \frac{(X[bar]_2-X[bar]_1)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } } ~~t_w

t_{H_0}= \frac{(101.7-101.28)-0}{\sqrt{\frac{(20.15)^2}{13} +\frac{(5.08)^2}{11} } } = 0.072

This test is one-tailed to the left, meaning that you'll reject the null hypothesis at small values of t. The p-value is also one-tailed and has the same direction as the test. To calculate it you have to first calculate the degrees of freedom of the Welch's t:

Df_w= \frac{(\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S^2_1}{n_1})^2 }{n_1-1}+\frac{(\frac{S^2_2}{n_2} )^2}{n_2-1}  }

Df_w= \frac{(\frac{5.08^2}{11} +\frac{20.15^2}{13} )^2}{\frac{(\frac{5.08^2}{11})^2 }{10} +\frac{(\frac{20.15^2}{13} )^2}{12} } = 13.78

The distribution is a Student's t with 13 degrees of freedom, then you can calculate the p-value as:

P(t₁₃≤0.072)= 0.4718

Using the p-value approach, the decision rule is:

If the p-value ≤ α, the decision is to reject the null hypothesis.

If the p-value > α, the decision is to not reject the null hypothesis.

The p-value is greater than the significance level, so the decision is to nor reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to support the claim that the average thickness pf the plastic coat processed at 150F is less than the average thickness pf the plastic coat processed at 125F.

I hope you have a SUPER day!

4 0
2 years ago
Which of the following is not a requirement of a standard form equation Ax+By=C? a)A ≥ 0. b)B ≥ 0. c)A and B are not both 0. d)A
Ghella [55]
<h2>Answer:</h2>

The following which is not a requirement of a standard form of equation Ax+By=C is:

        b)   B ≥ 0    

<h2>Step-by-step explanation:</h2>

We know that the standard equation of a line is given by:

        Ax+By=C

where A,B and C are integers and A is taken to be a non-negative integer i.e. (A≥0) also the greatest common factor of A,B and C is: 1.

Also A and B can't be both zero.

       Hence, the correct option is:

                Option: b

7 0
2 years ago
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