Integral of 2sin(2x) is -cos(2x)
from 0 to pi/2 (sub pi/2 minus sub 0 for x) and then solve
= -cos(2*pi/2)-(-cos0)
= -cos pi + cos 0
= 1 + 1
= 2
1: answer: 4^6 ( reduce the fraction with 4^3)
2: answer: 1 ( any nonzero expression raised to the power of 0 equals 1 )
3: answer 3^8
steps: (3^2)^4 = 3^2×4 ( to raise a power to another Power multiply the exponents)
3^2×4 = 3^8 ( multiply the 2 and the 4 exponent to get a 8 as a exponent )
Since complementary angles add up to 90 degrees, we simple take
and simplify it to
°
Given
on the interval 0 ≤ x ≤ 7, for maximum value, f'(x) = 0.
