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Artist 52 [7]
11 months ago
10

The average of six positive integers starting with a is equal to b. What is the average of five consecutive integers ending with

b?
a)a+1
b)a-1
C)a+2
d)a+3
e)a+4
Mathematics
1 answer:
kvasek [131]11 months ago
7 0

The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.

<h3>What is the average of five consecutive integers ending with b?</h3>

First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;

(a+a+2+a+4+a+6+a+8+a+10)/6 = b

6b=6a+30

b=a+5

Also, let the average of the consecutive intergers ending with b be denoted by; x.

(b+b-1+b-2+b-3+b-4)/5 = x

=(5b-10)/5

=b–2

The average, x=b – 2 (where b = a-5)

Ultimately, the value of the required average is; = a+5-2 = a+3.

Read more on average of integers;

brainly.com/question/24369824

#SPJ1

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Answer:

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Step-by-step explanation:

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∴ n = 3(11) = 33

∴ n = 33

<em>There are 20 pennies, 33 nickels and 11 quarters</em>

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