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Artist 52 [7]
10 months ago
10

The average of six positive integers starting with a is equal to b. What is the average of five consecutive integers ending with

b?
a)a+1
b)a-1
C)a+2
d)a+3
e)a+4
Mathematics
1 answer:
kvasek [131]10 months ago
7 0

The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.

<h3>What is the average of five consecutive integers ending with b?</h3>

First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;

(a+a+2+a+4+a+6+a+8+a+10)/6 = b

6b=6a+30

b=a+5

Also, let the average of the consecutive intergers ending with b be denoted by; x.

(b+b-1+b-2+b-3+b-4)/5 = x

=(5b-10)/5

=b–2

The average, x=b – 2 (where b = a-5)

Ultimately, the value of the required average is; = a+5-2 = a+3.

Read more on average of integers;

brainly.com/question/24369824

#SPJ1

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Colt1911 [192]

Part A:

We see that this pair of equations has 1 solution. On a graph, the solutions of 2 (or more) lines is where the lines intersect. In this case, since these lines intersect 1 time, they have 1 solution.

Part B:

As previously mentioned, the solutions of multiple lines is where the lines intersect. In this case, since they intersect at (4,4), that is the solution.

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3 years ago
A new roll of wrapping paper has 6 5/8 yards of paper. Drew used 2 1/6 yards from the roll to wrap a gift. Which equation most c
Sedbober [7]
First you have to make both fractions have the same denominator, so you can multiply each fraction by the others denominator.

5/8
To
(5*6)/(8*6)

And

1/6
To
(1*8)/(6*8)

Now it's 6 30/48 - 2 8/48

= 4 22/48

Now reduce to

= 4 11/24

So, 4 11/24 is the answer

3 0
3 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

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How to covert 11 pi over 12 to degrees
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When you convert 11pi over 12 in to degrees, you get 165°
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3 years ago
What is the measure of angle x? m&lt;x = ?
Ainat [17]
Hey there! :)

The total measure for triangles is 180°

You already know 2 angles. Add both angles and subtract from 180 to find x

37 + 82 = 119

180 - 119 = 61

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Hope this helps :)
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