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3 years ago

Help me pleaseeeeeeeeeeeeeee

Mathematics

1 answer:

dangina [55]3 years ago

7 0

Answer:

W=1000C/tc

Step-by-step explanation:

First multiply both side 1000: 1000C=Wtc

Divide both side by tc: 1000C/tc=W (t, c ≠0)

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Paula wants to buy 3 shirts and 2 belts. The shirts cost $16.89 each, and the belts cost $8.97 each. Paula has $45. Which of the

Mariana [72]

Answer:

Paula needs additional $23.61

Step-by-step explanation:

Given

$Shirts = 3$

$Belts = 2$

$Cost(shirt) = \$16.89$

$Cost(belt) = \$8.97$

$Amount = \$45$

Required

Estimate how much money is needed more

First, we need to estimate the total amount of 3 shirts and 2 belts:

$Total = Quantity * Cost$

$Total = 3 * \$16.89 + 2 * \$8.97$

$Total = \$50.67 + \$17.94$

$Total = \$68.61$

Subtract the amount with Paula from the calculated total.

$Difference = \$68.61-\$45$

$Difference = \$23.61$

Hence:

Paula needs additional $23.61

8 0

2 years ago

A random sample of 81 automobiles traveling on a section of an interstate showed an average speed of 60 mph. The distribution of

myrzilka [38]

Answer:

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(60,13.5)$

Where $\mu=60$ and $\sigma=13.5$

And for this case we select a sample size of n= 81. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error of the mean would be:

$\sigma_{\bar X} =\frac{13.5}{\sqrt{81}}= 1.5$

4.1.5

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(60,13.5)$

Where $\mu=60$ and $\sigma=13.5$

And for this case we select a sample size of n= 81. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error of the mean would be:

$\sigma_{\bar X} =\frac{13.5}{\sqrt{81}}= 1.5$

4.1.5

7 0

3 years ago

Solve the following system of equations graphically on the set of axes below.

ikadub [295]

Answer:

Step-by-step explanation:

I can't use the same graph that you have supplied, but I can show you what the answer looks like. Just use two points from my answer that will fit on your graph. Suggest points

Red line: (7,0) and (3,6)

Blue line: (3,0) and (0,3)