Answer:
Ordinal
Step-by-step explanation:
Level of measurement used in statistics summarizes what statistical analysis that is possible. There exist three types of level of measurement. The nominal, ordinal and Interval/Ratio level of measurement. Here, our primary focus will be the Ordinal level of measurement.
Ordinal level of measurement indicates the position in a sequence. In the military sector, the officer's rank is said to be Ordinal. This implies that the ordinal level of measurement categorizes variables according to hierarchy or ranks with a meaningful order. Still, the intervals and differences between the variables may not be equal.
Hi!
<h3>Use the distribution property</h3>
1.4t — 0.4 * t - 0.4 * —3.1 = 5.8
1.4t — 0.4t - 1.24 = 5.8
<h3>Simplify</h3>
1t - 1.24 = 5.8
<h3>Add 1.24 to both sides</h3>
1t - 1.24 + 1.24 = 5.8 + 1.24
1t = 7.04
<u>t = 7.04</u>
<h2>The answer is t = 7.04</h2>
Hope this helps! :)
-Peredhel
Answer:
all three sampling distributions appear to follow the normal distribution
Step-by-step explanation:
Sampling distribtuions follow a normal distribution.
Answer:
Some answers to the reducing fraction sheet
Q14 = 4/5 because divide 12 and 15 by 3
Q15=can't be reduced because 11 is a prime number so it can't be divided by anything
Q17=can't be reduced because 17 is a prime number
Q18=can't be reduced because 13 is a prime number
Q19=38/9 because 114 and 27 would be divided by 3
Q20= -1/1 because you would divide both 14,529 by itself would equal to - 1/1
I can only help you with this sheet I can't help you with the other one hope this was helpful! :)
Answer:
Reject Null Hypothesis given that P-value < ∝
Step-by-step explanation:
Applying the Five ( 5 ) step model and assuming ∝ = 0.05
First step : determine the Null hypothesis
H0 : Age and support for Anti-smoking = independent
Second step : Determine the alternate hypothesis
Ha : Age and support for Anti-smoking ≠ independent
Thirdly : Identify significance level ( ∝ ) = 0.05
4th step : Calculate the Test statistic and P-value
Chi-squared test = 36.1429 using excel function
P-value = 1 - CHISQ.DIST(36.1429, 1, TRUE) < 0.0001
finally : we can conclude that Age and support for Anti -smoking are not Independent hence we Reject The Null hypothesis. Given that
P-value < ∝
