Question

Two 2.5 kg physical science textbooks on a bookshelf are 0.14 m apart. What is the magnitude of the gravitational attraction between the books?

Answer 1

Answer:

Explanation:

According to Newton's laws of gravitation force of attraction is given by

F = GMm/R²

G = 6.67 X 10⁻¹¹

,M = 2.5 Kg ,

m = 2.5 Kg ,

R = .14 m

=

F = 6.67 X 10⁻¹¹ X 2.5 X 2.5 / 0.14²

= 2126.9 X 10 ⁻¹¹ N.

Answer 2

Answer:

2.13 x 10^-8 N

Explanation:

m1 = 2.5 kg

m2 = 2.5 kg

r = 0.14 m

According to the Newton's law of gravitation, the force of attraction between them is given by

F = G m1 x m2 / r^2

Where, G is the Universal Gravitational constant and the value of G

is 6.67 x 10^-11 Nm^2/kg^2

So, the force between the text books is

F = (6.67 x 10^-11 x 2.5 x 2.5) / (0.14 x 0.14)

F = 2.13 x 10^-8 N