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eimsori [14]
3 years ago
15

What lies beneath earth crust

Physics
2 answers:
riadik2000 [5.3K]3 years ago
5 0
Four layers: a rocky outer crust, a mantle of hot viscous rock, a liquid outer core, the seat of magnetism, and a solid, spinning inner core. I don't remember answering it again the correct way so here it is
nexus9112 [7]3 years ago
4 0
The Mantle lies underneath the crust.
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1 point
stiks02 [169]

Answer:

<h2>28,000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 800 × 35

We have the final answer as

<h3>28,000 N</h3>

Hope this helps you

3 0
3 years ago
The workdone In pulling a body which weighs 30N along a horizontal plane by a constant force of 20N is 320J. Find the distance m
sp2606 [1]

Answer: The answer is 800 J

Explanation:

4 0
2 years ago
A race car starts from rest and travels east along a straight and level track. For the first 5.0 ss of the car's motion, the eas
irina [24]

Answer:

The acceleration of the car is 7.85 m/s²

Explanation:

Given;

vx(t)= (0.910m/s³)t², given time traveled by the car 't' = 5.0 s

⇒To determine the velocity for 5 seconds, we substitute in 5.0 s for t

vx(5)= (0.910m/s³)(5s)²

       = (0.910m/s³)(25s²)

      vx = 22.75 m/s

⇒To determine the acceleration of the car when vx=12.0m/s

Acceleration is change in velocity per unit time

when vx=12.0m/s, our new equation becomes; 12 = (0.910m/s³)t²

Solving for t: t² = 12/0.91

                     t² = 13.187

                      t = √13.187 = 3.63 s

  Acceleration = Δv/Δt

                        = \frac{(22.75 - 12)m/s}{(5-3.63)s} = (\frac{10.75}{1.37}).\frac{m}{s^2}

  Acceleration = 7.85 m/s²

3 0
4 years ago
A lady walks 10 m to the north, then she turns and continues walking 30 m due east.
ANEK [815]

Answer:

The distance covered is 40 m and the displacement is 31,6m.

Explanation:

The distance covered is the sum of the two distances (10+30). The displacement is equal to the distance of the hipotenusa of the triangle that the two distances (10 m to north and 30m to east) create. Using the Pythagoras theorem the displacent is equal to the Square root of (30^2 +10^2) .

4 0
3 years ago
A 60 kg pupil runs for 600m in 1 minute uniformly calculate kinetic energy​
AURORKA [14]

velocity = traveled distance ÷ time of the traveled distance is seconds

velocity = 600 ÷ 60

velocity = 10 m/s

_________________________________

Kinetic Energy = 1/2 × mass × ( velocity )^2

KE = 1/2 × 60 × ( 10 )^2

KE = 30 × 100

KE = 3000 j

8 0
3 years ago
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