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3 years ago

Which question asks for an opinion?

Physics

1 answer:

blsea [12.9K]3 years ago

5 0

Answer:

Explanation:

It says is it a good idea the person so 1 person can say no and the other one can say yes so it is asks for a opinion

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Today s electric generators work on the same principle as the dynamo invented by _____.

cluponka [151]

The answer is D. Michael Faraday

6 0

4 years ago

If you increase the force on an object, its acceleration

Snezhnost [94]

Answer:

True!

Explanation:

if you increase the force on an object, its acceleration

pls mark me brainliest

5 0

4 years ago

4 points

zubka84 [21]

(a) 25lx

(b) 11.11lx

<u>Explanation:</u>

Illuminance is inversely proportional to the square of the distance.

So,

$I = k\frac{1}{r^2}$

where, k is a constant

So,

(a)

If I = 100lx and r₂ = 2r Then,

$I_2 = k\frac{1}{(2r)^2}$

Dividing both the equation we get

$\frac{I_1}{I_2} = \frac{k}{r^2} X\frac{(2r)^2}{k} \\\\\frac{I_1}{I_2} = 4\\\\I_2 = \frac{I_1}{4}\\\\I_2 = \frac{100}{4} = 25lx$

When the distance is doubled then the illumination reduces by one- fourth and becomes 25lx

(b)

If I = 100lx and r₂ = 3r Then,

$I_2 = k\frac{1}{(3r)^2}$

Dividing equation 1 and 3 we get

$\frac{I_1}{I_2} = \frac{k}{r^2} X\frac{(3r)^2}{k} \\\\\frac{I_1}{I_2} = 9\\\\I_2 = \frac{I_1}{9}\\\\I_2 = \frac{100}{9} = 11.11lx$

When the distance is tripled then the illumination reduces by one- ninth and becomes 11.11lx

3 0

3 years ago

PLS HELP ASAP!

Oduvanchick [21]

2.09sec

Add them together then divide by three because there are three numbers

4 0

3 years ago

A 21 kg chair initially at rest on a horizontal floor requires a 175 N horizontal force to set it in motion. Once the chair is i

Alika [10]

Answer: $\mu =0.85$

Explanation:

Given

mass of chair m=21 kg

Force required to set chair in motion is 175 N

Once the chair is in motion 137 N is require to move it with constant velocity

i.e. 175 N is the amount of force needed to just overcome static friction and 137 is the kinetic friction force

thus

$f_s(static\ friction)=\mu \cdot N$

where $\mu$ is the coefficient of static friction and N is Normal reaction

$N=mg$

$f_s=\mu mg$

$\mu mg=175$

$\mu =\frac{175}{21\times 9.8}$

$\mu =0.85$

8 0

3 years ago