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tensa zangetsu [6.8K]

2 years ago

12

The density of a solid material depends on two things .Name those two things

2 answers:

Nostrana [21]2 years ago

8 0

The density of an object is Density= Mass/Volume

Amiraneli [1.4K]2 years ago

5 0

Mass of an individual atoms or molecules

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Three common elements that can reorient their electrons into magnetic domains and become magnetic are iron, nickel, and ________

ohaa [14]

Answer:

Cobalt

Explanation:

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2 years ago

PLEASE HELP ASAP!! THIS IS DUE IN 15 MUNITES!! Explain what a Precipitate (Not Precipitation) is and tell me if it is a Physical

Amiraneli [1.4K]

Answer:

A precipitate is a solid that separates out of a liquid solution when it is supersaturated (insoluble). This is a chemical change.

Explanation:

Precipitation is when a chemical substance converts into a solid from a solution by converting the substance into an insoluble form or a super-saturated solution. When the reaction occurs in a liquid solution, the solid formed is called the precipitate.

Hope that helps.

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2 years ago

Who is the father of nuclear physics?

bija089 [108]

Answer: the father of the nuclear physics is Ernest Rutherford

Explanation:

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2 years ago

A residential subdivision encompasses 1100 acres with a housing density of four houses per acre. Assume that a high-value reside

aleksandrvk [35]

Answer:

(a). The average daily demand of this subdivision is 2444.44 gallon/min.

(b). The design-demand used to design the distribution system is 2444.44 gallon/min.

Explanation:

Given that,

Area = 1100 acres

Number of house in 1 acres = 4

$\text{Number of house in 1100 acres} = 4\times1100$

$\text{Number of house in 1100 acres} = 4400$

Per house water demand = 800 g/day/house

(a). We need to calculate the average daily demand of this subdivision

Using formula for average daily demand

$\text{average daily demand}=house\times\text{Per house water demand}$

$\text{average daily demand}=4400\times800\ gallon/day$

$\text{average daily demand}=3520000\ gallon/day$

$\text{average daily demand}=\dfrac{3520000}{24\times60}\ gallon/min$

$\text{average daily demand}=2444.44\ gallon/min$

The average daily demand of this subdivision is 2444.44 gallon/min.

(b). We need to calculate the design-demand used to design the distribution system

Using formula for the design-demand

$\text{design demand}=(Q_{max})daily\times\text{fire flow}$

$\text{design demand}=1.64\times2444.4\times1000$

$\text{design demand}=4008816\ gallon/m$

Hence, (a). The average daily demand of this subdivision is 2444.44 gallon/min.

(b). The design-demand used to design the distribution system is 2444.44 gallon/min.

8 0

2 years ago

Can someone help me on how to do this?

Galina-37 [17]

Explanation:

Recall that

$1\:\text{micron} = 1\:\mu\text{m} = 10^{-6}\:\text{m}$ so the speed of the bacterium is

$v = \dfrac{6.82×10^{-6}\:\text{m}}{3.5\:\text{s}} = 1.9×10^{-6}\:\text{m/s}$

Next, we convert this speed to km/hr. Recall that

$1\:\text{km} = 1000\:\text{m}$

$1\:\text{hr} = 60\:\text{minutes} = 3600\:\text{s}$

Therefore,

$1.9×10^{-6}\:\dfrac{\text{m}}{\text{s}}×\left(\dfrac{1\:\text{km}}{1000\:\text{m}}\right)×\left(\dfrac{3600\:\text{s}}{1\:\text{hr}}\right)$

$= 6.8×10^{-6}\:\text{km/hr}$

8 0

2 years ago