Answer:
Explanation:
Let's analyze the situation presented in order to know which answer is correct.
When the stick collides with the puck, it exerts a force for a certain time and discants. / After this time the horizontal force decreases to zero and the disk continues to move by the action of the initial velocity on the x axis and the acceleration of gravity on the y axis.
Therefore, after the collision, the only force that acts on the disk is the gravitational attractive force (WEIGHT), directed on the axis and in a negative direction.
The correct answer is:
C) Since there is no frictional force exerted on the puck, a normal force is not exerted on the puck, but the gravitational force is exerted on the puck
Because they are conducting, when you bring them together the charge is split equally among the two spheres (because they have the same radius the amount of charge is also equal). Now they will repel each other because of the net charge on each with the same polarity.
Answer:
electric field amplitude is 0.1133 V/m
Explanation:
given data
energy density = 5.69 × 10^−14 J/m3
speed of light = 2.99792 × 10^8 m/s
permeability of free space = 4π × 10^−7 N/A2
to find out
corresponding electric field amplitude
solution
we know electric filed amplitude E is
E = BC ..............1
so first we find magnetic filed B from energy density
that is energy density
u = B²/ 2µ
so B = √2µu
put value
B = √2(4π×
×5.69 × 
)
B = 3.780645 × 
so from equation 1
E = 3.780645 × (2.99792 × 10^8)
E = 0.1133
electric field amplitude is 0.1133 V/m
Answer:
The Force exerted on the student by crate will be 100 N.
Explanation:
As per the given Question student is trying to push the crate in right direction with the force of 100N.
And we know that, Newton's third law states that every action has equal and opposite reaction.
So from the Newton's 3rd law of motion it is very clear the student must be experiencing the same amount of force which he is applying.
