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3 years ago

Jonas buys a new hat that costs 9.05 Kara buys a new t shirt

Mathematics

1 answer:

bixtya [17]3 years ago

5 0

Is there anything else to the problem

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Help please anybody

Sedbober [7]

put in an positive number for x and check

2 - 5 = -3

5 - 2 = 3

- 2 + 5 = 3

5 + (-2) = 2

so the only different one is the first

4 0

3 years ago

In order to test for the significance of a regression model involving 4 independent variables and 47 observations, the numerator

Karolina [17]

Answer:

c. 4 and 42

Step-by-step explanation:

Given

$p = 4$ -- independent variables

$n = 47$ ---- observations

Required

The numerator and denominator degrees of freedom

The denominator degrees of freedom is:

$df =n - p - 1$

$df =47 - 4 - 1$

$df =42$

For the numerator, we have:

$df = p$

$df = 4$

8 0

3 years ago

Determine the area of the given region under the curve (1/x^4) [1,2]

Nikolay [14]

Answer:

$\displaystyle \frac{7}{24}$

General Formulas and Concepts:

Algebra I

Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

[Area] Limits of Riemann's Sums - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Step-by-step explanation:

Step 1: Define

$\displaystyle f(x) = \frac{1}{x^4} \\ \ [1, 2]$

Step 2: Find Area

[Integral] Set up area: $\displaystyle \int\limits^2_1 {\frac{1}{x^4}} \, dx$
[Integral] Rewrite: $\displaystyle \int\limits^2_1 {x^{-4}} \, dx$
[Integral] Reverse Power Rule: $\displaystyle \frac{-1}{3x^3} \bigg| \limits^2_1$
[Area] Fundamental Theorem of Calculus: $\displaystyle \frac{7}{24}$