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pentagon [3]
3 years ago
5

,,,,,,,,,,,,,,,,,,,,,,,,,

Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0

\dfrac{\dfrac{x}{4}+\dfrac{1}{8}}{\dfrac{x^2}{4}}=\left(\dfrac{2\cdot x}{2\cdot4}+\dfrac{1}{8}\right):\dfrac{x^2}{4}=\left(\dfrac{2x}{8}+\dfrac{1}{8}\right)\cdot\dfrac{4}{x^2}\\\\=\dfrac{2x+1}{8}\cdot\dfrac{4}{x^2}=\dfrac{2x+1}{2}\cdot\dfrac{1}{x^2}=\dfrac{2x+1}{2x^2}\to A.

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Hello there!

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