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3 years ago

How to solve the equation

Mathematics

1 answer:

wariber [46]3 years ago

5 0

Hey there!

So it's mentioned that the line is parallel, hence their gradient are equals.

From the eqn, y = 2x + 1 , you'll find that the gradient is 2 (conveniently, the equation of the line is directly derived from y=mx+c, where m is the gradient.)

Using the coordinates (2, -1) as the line passes through those points, make a new equation (with y=mx+c) with those points and the gradient 2 in order to find constant c.

-1=(2)(2) + c
c=-5

hence, the equation is y=2x-5.

The whole working is actually very short so I hope I didn't overcomplicate things :(

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NEED HELP WITH THESE QUESTIONS

amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

$\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =$

Applying double C we have:

$\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =$

By definition of multiplication of powers of the same base we have to place the same base and add the exponents: $\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =$

Canceling common terms:

$\frac {mn ^ 5} {p ^ 4}$

Answer:

Option A

Question 2:

We should simplify the following expression:

$\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}$

So, we have:

$\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =$

Simplifying common terms:

$\frac {1} {y ^ 2z ^ 2}$

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

$r ^ 2 + 7r + 10$ : We look for two numbers that multiplied give 10 and added 7:

$(r + 5) (r + 2)$

$r ^ 2-5r-50:$ We look for two numbers that multiplied give -50 and added -5:

$(r-10) (r + 5)$

$3r-30 = 3 (r-10)$

Rewriting the given expression we have:

$\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =$

We simplify common terms in the numerator and denominator we have:

$(r + 2)$

Answer:

Option D

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3 years ago

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evablogger [386]

Answer:

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Answer:

Ok soo.

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