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4 years ago

How much more light does an 8-meter telescope gather than a 2-meter telescope? view available hint(s)?

1 answer:

7 0

The light gathering of a telescope goes as the area of the telescope, therefore as the square of the aperture:
$P= \frac{D_1^2}{D_2^2}$
where D is the aperture of the telescope.
Therefore, using D1=8 m and D2=2 m, we find
$P= \frac{8^2}{2^2}=16$
So, the larger telescope will collect 16 times more light than the smaller one.

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If an electrically neutral atom has 4 protons and 4 neutrons and it loses 2 electrons, what is its charge?

Travka [436]

A) Because the 2 missing electrons leave 2 protons without counterpart (the neutrons don;t matter at all here)

3 0

4 years ago

undefinedIn a gasoline engine, the area in the cylinder head where the air-and-fuel mixture is burned is called the

ololo11 [35]

Answer:

Combustion chamber

Expalnation

Gasoline engine,

Gasoline engine is a type of internal-combustion engines in this engine when in the combustion chamber air and fuel mixture is burned with ignition initiated by an electric spark that time power is generated.

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3 years ago

Given a 3.00 μF capacitor, a 7.75 μF capacitor, and a 5.00 V battery, find the charge on each capacitor if you connect them in t

USPshnik [31]

Answer:

a) Q1= Q2= 11.75×10^-6Coulombs

b) Q1 =15×10^-6coulombs

Q2 = 38.75×10^-6coulombs

Explanation:

a) For a series connected capacitors C1 and C2, their equivalent capacitance C is expressed as

1/Ct = 1/C1 + 1/C2

Given C1 = 3.00 μF C2 = 7.75μF

1/Ct = 1/3+1/7.73

1/Ct = 0.333+ 0.129

1/Ct = 0.462

Ct = 1/0.462

Ct = 2.35μF

V = 5.00Volts

To calculate the charge on each each capacitors, we use the formula Q = CtV where Cf is the total equivalent capacitance

Q = 2.35×10^-6× 5

Q = 11.75×10^-6Coulombs

Since same charge flows through a series connected capacitors, therefore Q1= Q2=

11.75×10^-6Coulombs

b) If the capacitors are connected in parallel, their equivalent capacitance will be C = C1+C2

C = 3.00 μF + 7.75 μF

C = 10.75 μF

For 3.00 μF capacitance, the charge on it will be Q1 = C1V

Q1 = 3×10^-6 × 5

Q1 =15×10^-6coulombs

For 7.75 μF capacitance, the charge on it will be Q2 = 7.75×10^-6×5

Q2 = 38.75×10^-6coulombs

Note that for a parallel connected capacitors, same voltage flows through them but different charge, hence the need to use the same value of the voltage for both capacitors.

7 0

3 years ago

What keeps the balanced rock balanced

pogonyaev

Hello,

Here is your answer:

The proper answer to this question is "because of there substantial size the rock rests on another rock which keeps it balanced".

If you need anymore help feel free to ask me!

Hope this helps!

5 0

3 years ago

The specific heat of aluminum is 0.90 J/gC . How much heat is given off when 25 grams of aluminum is cooled from 55 C to 25 C?

xxMikexx [17]

Answer:

Q = 675 [J]

Explanation:

We can calculate the amount of heat transfer by means of the following expression that includes the mass and temperature change in a body as a function of the specific heat.

$Q=m*C_{p}*(T_{initial}-T_{final})$

where:

m = mass = 25 [gr]

Cp = specific heat = 0.9 [J/g*°C]

Tinitial = 55 [°C]

Tfinal = 25 [°C]

$Q=25*0.9*(55-25)\\Q=675 [J]$

4 0

3 years ago