Answer:
106.52 minutes
Explanation:
Given:
Initial distance between Carl and Isaac = 175 miles
speed of Isaac = 65 mph
Speed of Carl = 50 mph
Now, the Carl starts after 35 minutes, but the Isaac has already started so the distance covered by Isaac in 35 minutes will be
=
= 37.91 miles
Therefore,
the distance left between Isaac and Carl = 175 - 37.91 = 137.09 miles
Since Isaac and Carl are moving towards each other,
therefore the relative speed between the both = 65 + 50 = 115 mph
Hence, the time taken to meet =
or
The time taken to meet = 1.192 hours
or
The time taken = 1.192 × 60 = 71.52 minutes
Therefore the total time Isaac have been travelling = 71.52 + 35
= 106.52 minutes
Answer:
24.32 V/m
Explanation:
We are given that
The distance between the points A and B on two equipotential lines=d=
By using
We have to find the average electric field in (volt/m) at the mid-point C expressed to one decimal places.
We know that the electric field=
Using the formula
Electric field=E=
They will accelerate the same amount but in opposite directions. In physics, a collision is any event wherein or greater our bodies exert forces on each other in a pretty brief time.
The mean loose time for a molecule in a fluid is the common time between collisions. The imply unfastened path of the molecule is made of the average velocity and the mean unfastened time. These principles are used inside the kinetic concept of gases to compute shipping coefficients including viscosity.
Collision, also known as an effect, in physics, is the surprising, forceful coming collectively in direct touch of two bodies, along with, as an example, billiard balls, a golf membership, and a ball, a hammer, and a nail head, two railroad vehicles while being coupled collectively, or a falling item and a ground.
The verb collide has roots in the Latin word collider, which comes from col- or collectively and leader, to strike or harm, like planes that collide in mid-air.
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Answer:
The Tension T is 42120N
The Horizontal force component is 18322.2N
The Vertical force component is - 4729N
Explanation:
First, you have to find the angle between the drawbridge and the cable using sine and cosine rule. This will result in angle 44.2°. Hence, the angle between the horizontal axis and the cable will be 64.2° (44.2° + 20°).
Having done that, you apply two conditions of equilibrium.
1. THE VECTOR SUM OF ALL FORCES EQUAL ZERO.
∑Fx = 0
∑Fx = Rx - Tcos64.2 = 0
Rx = 0.435T
∑Fy = 0
∑Fy = Ry + Tsin64.2 - W - w = 0
W = 2000kg × 9.8 = 19600N
w =1000kg × 9.8 = 9800N
Ry + 0.9T = 29400N
Ry = 29400 - 0.9T
2. THE SUM TOTAL OF TORQUES EQUALS ZERO
Rx: τ = 0
Ry: τ = 0
T: τ = 5 × Tsin44.2
= 3.49T m
W: τ = 4 × 19600sin90
= 78400Nm
w: τ = 7 × 9800sin9
= 68600Nm
Note:
Rx = x component of Reaction force
Ry = y component of Reaction force.
T = Tension
W = weight of bridge
w = weight of Sir Lance a Lost and his steed
τ = torque
Note: The torque of Tension is counter clockwise while that of the weights is clockwise.
Hence,
∑τccw = ∑τcw
3.49T = 78400 + 68600
3.49T = 14700Nm
T = 147000/3.49
T = 42120N
Rx = 0.435 × 42120
Rx = 18322.2N
Ry = 29400N - (0.9×42120)N
Ry = 29400 - 34129
Ry = -4729N
Note: Ry being negative means that the hinge of the drawbridge exerts a downward force.