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skelet666 [1.2K]
4 years ago
6

Which is f(5) for the function -2x^2+2x-3

Mathematics
1 answer:
sweet-ann [11.9K]4 years ago
3 0

Answer:

f(5)=-43

Step-by-step explanation:

Hope this helps!!!!!!

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15 more than twice a number is -23
Ymorist [56]

Answer:

2x + 15 = -23

x = -19

Step-by-step explanation:

2x + 15 = -23

2x+ 15-15 = -23 -15

2x = -38

2/2x = -38/2

x = -19

3 0
4 years ago
Find the values of the pronumerals in this diagram. Write down the reason in each case.
timofeeve [1]

Answer:

see explanation

Step-by-step explanation:

a and 85 form a straight angle and are supplementary, thus

a + 85 = 180 ( subtract 85 from both sides )

a = 95

b and 85 are vertical angles and are congruent, thus

b = 85

c and 85 are corresponding angles and congruent, thus

c = 85

c and d are vertical angles and congruent, thus

d = 85

In conclusion

a = 95, b = 85, c = 85, d = 85

5 0
3 years ago
Solve the following...<br>6x - 5 = -9x -9​
sergiy2304 [10]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:x = -\cfrac{4}{15}

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: 6x - 5 =  - 9x - 9

[ add 9x and 5 on both sides ]

\qquad \tt \rightarrow \: 6x - 5 + 9x + 5 =  - 9x - 9 + 9x + 5

\qquad \tt \rightarrow \: 6x + 9x =  - 9 + 5

\qquad \tt \rightarrow \: 15x = -  4

\qquad \tt \rightarrow \: x =  -  \cfrac{4}{15}

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

7 0
2 years ago
Read 2 more answers
The amount of oil used by a ship traveling at a uniform speed varies jointly with the distance and the square of the speed. the
muminat
A = kdv^2    where A = amount oil d = distance and v = speed and k is a constant
so 
30 = k*85*42^2
Now solve for k:-
k = 30 / (85*42^2) =     0.00020008

So when d = 26 and v = 54

Amount of oil A = 0.00020008 * 26*54^2
                          =  15.2 barrels

4 0
4 years ago
Solve this system of equations<br><br> 3x-5y=7<br> 4x+10y=16
seropon [69]
Solve the following system:
{3 x - 5 y = 7 | (equation 1)
{10 y - 4 x = 16 | (equation 2)


Swap equation 1 with equation 2:
{-(4 x) + 10 y = 16 | (equation 1)
{3 x - 5 y = 7 | (equation 2)

Add 3/4 × (equation 1) to equation 2:
{-(4 x) + 10 y = 16 | (equation 1)
{0 x+(5 y)/2 = 19 | (equation 2)


Divide equation 1 by 2:
{-(2 x) + 5 y = 8 | (equation 1)
{0 x+(5 y)/2 = 19 | (equation 2)


Multiply equation 2 by 2:
{-(2 x) + 5 y = 8 | (equation 1)
{0 x+5 y = 38 | (equation 2)

Divide equation 2 by 5:
{-(2 x) + 5 y = 8 | (equation 1)
{0 x+y = 38/5 | (equation 2)

Subtract 5 × (equation 2) from equation 1:
{-(2 x)+0 y = -30 | (equation 1)
{0 x+y = 38/5 | (equation 2)

Divide equation 1 by -2:
{x+0 y = 15 | (equation 1)
{0 x+y = 38/5 | (equation 2)
Collect results:
Answer:  {x = 15
                {y = 38/5 or 7.6 decimal
4 0
4 years ago
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