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3 years ago

Solve |-3d | =15 please lol

Mathematics

1 answer:

Keith_Richards [23]3 years ago

7 0

Answer:

$d=-5 \text{ or } d=5$

Step-by-step explanation:

$|-3d|=15\\\\-3d=15 \text{ or } -3d=15\\\\\frac{-3d=15 \text{ or } -3d=15}{-3}\\\\\boxed{d=-5 \text{ or } d=5}$

Hope this helps.

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lara31 [8.8K]

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3 years ago

Use the Distributive Property to find (z−5)(z+3).

Anastasy [175]

Consider, $(z-5)(z+3)$ . Let's say $a = z-5$ then the problem reduces to $a(z+3)=za+3a$ . (Do you understand this step?)

So then replacing a again with our definition we get, $z(z-5)+3(z-5)=z^2-5z+3z-15=z^2-2z-15$ .

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3 years ago

Can someone please help

Fynjy0 [20]

Answer:

angle C = 78

angle D = 108

Step-by-step explanation:

the measure of angle A is 102

To find the measure of angle C

let Angle C be x

102 + x = 180 (linear pair)

x = 180 -102

x = 78

angle C = 78

angle B = 78 (vertically opposite angles are equal)

angle D = 108 (vertically opposite angles are equal)

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2 years ago

The sum of 3y and 5 is 47

Daniel [21]

if 3y + 5 = 47

then

y=14

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3 years ago

Does (-2)^n/( 3^n+1) converge or diverge?

hodyreva [135]

$\left|\dfrac{(-2)^n}{3^n+1}\right|=\dfrac{2^n}{3^n+1}$

As $n\to\infty$ , the sequence $a_n=\left(\dfrac23\right)^n$ converges to zero.

If you're talking about the infinite series

$\displaystyle\sum_{n\ge0}\dfrac{(-2)^n}{3^n+1}$

well we've shown by comparison that this series must also converge because we know any geometric series $\sum\limits_n r^n$ will converge as long as $|r|$ .

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2 years ago