Paul’s account balance is less than -$50. What is a possible balance for paul’s account? Explain.
1 answer:
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You can get all the terms on one side, and then solve for x by any means:
Factor out a -2:
Factor this equation:
I will use the AC method. To use it, first multiply a and c (in ax^2 + bx +c):
Now, look for two numbers that multiply to -12 and add to -11. Obviously these numbers are -12 and 1. (-12*1 = -12 and -12+1 = -11). Now, because of rules, you set it up in a Punnett square:
4x^2 -12x
x -3
Now, we find common factors of the terms in rows:
_x_______-3__
4x| 4x^2 -12x
1 | x -3
So, you can use this to write an equivalent expression to the quadratic given:
Now, we known the factors are (solve for x): 3 and -1/4.
Factor out a -2:
Factor this equation:
I will use the AC method. To use it, first multiply a and c (in ax^2 + bx +c):
Now, look for two numbers that multiply to -12 and add to -11. Obviously these numbers are -12 and 1. (-12*1 = -12 and -12+1 = -11). Now, because of rules, you set it up in a Punnett square:
4x^2 -12x
x -3
Now, we find common factors of the terms in rows:
_x_______-3__
4x| 4x^2 -12x
1 | x -3
So, you can use this to write an equivalent expression to the quadratic given:
Now, we known the factors are (solve for x): 3 and -1/4.
Answer:
The probability that he teleports at least once a day =
Step-by-step explanation:
Given -
Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation options teleport ride a dragon or walk to work and in the evening he has the same three choices for his trip home.
Total no of outcomes = 3
P( He not choose teleport in the morning ) =
P( He not choose teleport in the evening ) =
P ( he choose teleports at least once a day ) = 1 - P ( he not choose teleports in a day )
= 1 - P( He not choose teleport in the morning ) P( He not choose teleport in the evening )
=
=