Using the <em>normal distribution and the central limit theorem</em>, it is found that the power of the test is of 0.9992 = 99.92%.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is
.
- The standard deviation is
.
- A sample of 30 is taken, hence
.
The power of the test is given by the probability of a sample mean above 8, which is <u>1 subtracted by the p-value of Z when X = 8</u>, so:
By the Central Limit Theorem:
has a p-value of 0.0008.
1 - 0.0008 = 0.9992.
The power of the test is of 0.9992 = 99.92%.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213
Answer: linear function is any function that graphs to a straight line. What this means mathematically is that the function has either one or two variables with no exponents or powers. If the function has more variables, the variables must be constants or known variables for the function to remain a linear function.
Step-by-step explanation:
Answer:
350 people can fit into 42 rooms
Step-by-step explanation:
So we can write it as a relation fraction equation:
Where:
x represents the people can fit in 42 rooms
Therefore, <u>350 people can fit into 42 rooms.</u>
I hope it helps you!
Answer:
Mean: 8 and MAD: 1.2
Step-by-step explanation:
Given a data with :
Mean = 20 ; mean absolute deviation (MAD) = 3.1
DATA with a low mean and variability Than The above from the options given :
The most appropriate option is : Mean: 8 and MAD: 1.2 ; because both values of the mean and mean absolute deviation are lesser than the value given.
I think the answer is -15. Hope I helped
