Answer:
A score of 150.25 is necessary to reach the 75th percentile.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.
This means that 
What score is necessary to reach the 75th percentile?
This is X when Z has a pvalue of 0.75, so X when Z = 0.675.




A score of 150.25 is necessary to reach the 75th percentile.
Hello,
Answer A
(3x-4)²-(x+7+x²+2)=9x²-24x+16-x-x²-9
=8x²-25x+7
+3 . I think, hope this helps
Answer:
The answer is 4.
Step-by-step explanation:
Vertical Angles are congruent.
You plug in 4 for x and you multiply the two to get you 112.
112-2=110, making the two angles the same angle measure.
Hope this helps :)