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ioda
3 years ago
13

A necktie costing $30.00 per dozen and selling for $5 each (be careful- find the cost of one tie before you subtract.) 0.25 2.50

25.00 35.00
Mathematics
2 answers:
Alenkasestr [34]3 years ago
7 0

Answer:

2.50

Step-by-step explanation:

Vikki [24]3 years ago
5 0
Here is the answer to the problem above. Given that a necktie is sold per dozen and costs $30.00 and sells it for $5. In order for us to know the price per necktie, we just have to divide 30 by 12 since one dozen is 12. 30 divided by 12, and the answer is 2.5. So the cost of one tie is $2.5. Hope this answers your question.
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F(x)=(x+4)(x-2)(x+4)(x+4)<br><br> What is the multiple zero? Multiplicity is?
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Read 2 more answers
Simplify
OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}

we need to simplify that

x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)

so we can continue

\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}

and we can put all together

\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}

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