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2 years ago

Of the 21 children at a park, 5 of them are playing on the swings. What is the approximate

Mathematics

1 answer:

Bond [772]2 years ago

3 0

The Answer Is B

Use proportions to find x% of the children playing on the swings.

$\frac{21}{100} = \frac{5}{x\%}$

$x = 23.80952380\%$

Meaning B is correct.

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Melissa used 4 cups of sugar to bake 54 cookies. If she’s only used 1 cup of sugar, what would be an equivalent ratio of cups to

daser333 [38]

Answer:

$\frac{2}{27}$

Step-by-step explanation:

We have given that melissa used 4 cups of sugar to bake 54 cookies.

That means 1 cup of sugar will be used to bake $\frac{54}{4}=\frac{27}{2}$ by unitary method

We have to find the ratio of cups to the cookies

We are using 1 cup of sugar

And cookies will be $\frac{27}{2}$

$\text{equivalent ratio}=\frac{1}{\frac{27}{2}}=\frac{2}{27}$

3 0

3 years ago

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the instanteous rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at exactly t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0

3 years ago

F(x)=9x^2 g(x)= sqrt 12-x/3 (f o g)(-4)

Slav-nsk [51]

$f(x)=9x^2 \\ g(x)=\frac{\sqrt{12-x}}{3} \\$ So,first step is to write $(fog)(-4)) =f[g(-4)] \\$

Now we start from inner paranthesis ,we need to first find value of $g(-4) =\frac{\sqrt{12-(-4)}}{3}\\ =\frac{\sqrt{12+4}}{3}\\
=\frac{\sqrt{16}}{3}\\
=\frac{4}{3}\\
(fog)(-4)) =f[g(-4)] =f(\frac{4}{3}) =9(4/3)^{2} =9*(16/9) =144/9 =16$

8 0

3 years ago