All categories

3 years ago

Help with geometry!!

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

4 0

Answer:

y = x

Step-by-step explanation:

Slope-intercept form is the form that looks like

... y = mx + b . . . . . . for slope m and y-intercept b

The line connecting points D and E has slope 1 and y-intercept 0, so the equation is ...

... y = 1·x + 0

... y = x . . . . . . without the identity elements

_____

<em>Comment on the marked choice</em>

The choice that is marked is the equation in <em>point-slope form</em> using the point E (4, 4). That is not the form requested by the problem.

You might be interested in

Jack’s bank statement shows an account balance of –$25.50. Which describes the magnitude, or size, of the debt in dollars? $50.5

mash [69]

Answer:

$25.50

Step-by-step explanation:

because the magnitude of the debt is the distance from zero.

8 0

3 years ago

Read 2 more answers

The Hawks are starting a babysitting business. They charge an initial deposit of $25 and a rate of $4 an hour. A linear model is

Sauron [17]

What’s the question so I can answer it.

7 0

3 years ago

45 degreese is used in a pie chart to reperesent 6 people. How many people were there altogehter?

KatRina [158]

We can solve this problem by the rule of three.
A complete pie chart has 360º.

45º----------------------6 people
360º-------------------- x

x=(360º*6 people) / 45º=48 people.

Answer; 48 people.

6 0

3 years ago

Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu

kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

$f(x) = {x}^{5} - {x}^{3} + 6$

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

$f'(x) = 5 {x}^{4} - 3 {x}^{2}$

At turning point f'(x)=0.

$5 {x}^{4} - 3 {x}^{2} = 0$

This implies that,

${x}^{2} (5 {x}^{2} - 3) = 0$

${x}^{2} = 0 \: or \: 5 {x}^{2} - 3 = 0$

$x = - \frac{ \sqrt{15} }{5} \: or \: x = 0 \: \: or \: x =\frac{ \sqrt{15} }{5}$

We plug this values into the original function to obtain the y-values of the turning points

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} +750)) \:and \: (0, - 6) \: and\: ( \frac{ \sqrt{15} }{5} , \frac{1}{125} ( - 6 \sqrt{15} +750))$