All categories

3 years ago

What is the momentum of a 5 kg object that has a velocity of 1.2 m/s?

2 answers:

8 0

In the given question all the required details are given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.
We know the equation of finding momentum as
Momentum = mass * velocity
= 5 * 1.2
= 6
So the momentum of the object is 6 Newton.

coldgirl [10]3 years ago

5 0

Answer: P = 6 kg m/s

Explanation:

Momentum of an object is given by the product of mass and velocity. Any object in motion has momentum.

It is given by:

P = m v

where m is the mass and v is the velocity.

Here, m = 5 kg

v = 1.2 m/s

Thus, P = m v = 5 kg × 1.2 m/s² = 6 kg.m/s²

You might be interested in

What was the main view how the world worked geologically prior to the 1960s? It was generally believed that continents and ocean

attashe74 [19]

Answer:

It was generally believed that mountains were produced by vertical forces

Explanation:

The main view of the world worked geologically prior to the 1960s was that the mountains were formed by the vertical forces of nature.

The early people prior to 1960s believed in many different natural phenomenons and they give their own reasons for their occurrence. But later many researchers and geophysicists studied the formation of the earth and came with possible answers to these questions.

Thus the answer is

" It was generally believed that mountains were produced by vertical forces."

3 0

3 years ago

The rms (root-mean-square) speed of a diatomic hydrogen molecule at 50∘C is 2000 m/s. Note that 1.0 mol of diatomic hydrogen at

denis-greek [22]

Answer:

A) d. (1/4)(2000m/s) = 500 m/s

B) c. 4000 J

C) f. None of the above (2149.24 m/s)

Explanation:

The translational kinetic energy of a gas molecule is given as:

K.E = (3/2)KT

where,

K = Boltzman's Constant = 1.38 x 1^-23 J/K

T = Absolute Temperature

but,

K.E = (1/2) mv²

where,

v = root mean square velocity

m = mass of one mole of a gas

Comparing both equations:

(3/2)KT = (1/2) mv²

v = √(3KT)/m _____ eqn (1)

FOR HYDROGEN:

v = √(3KT)/m = 2000 m/s _____ eqn (2)

FOR OXYGEN:

velocity of oxygen = √(3KT)/(mass of oxygen)

Here,

mass of 1 mole of oxygen = 16 m

velocity of oxygen = √(3KT)/(16 m)

velocity of oxygen = (1/4) √(3KT)/m

using eqn (2)

velocity of oxygen = (1/4)(2000 m/s) = 500 m/s

K.E = (3/2)KT

Since, the temperature is constant for both gases and K is also a constant. Therefore, the K.E of both the gases will remain same.

K.E of Oxygen = K.E of Hydrogen

K.E of Oxygen = 4000 J

using eqn (2)

At, T = 50°C = 323 k

v = √(3KT)/m = 2000 m/s

m = 3(1.38^-23 J/k)(323 k)/(2000 m/s)²

m = 3.343 x 10^-27 kg

So, now for this value of m and T = 100°C = 373 k

v = √(3)(1.38^-23 J/k)(373 k)/(3.343 x 10^-27 kg)

v = 2149.24 m/s

8 0

3 years ago

4. As Juan is going to take a shower, the soap falls out of the soap dish on to the

LiRa [457]

The coefficient of friction between the soap and the floor is 0.081

If Juan steps on the soap with a force of 493 N, this is her weight, W. This weight also equals the normal reaction on the floor, N.

We know that frictional force F = μN where μ = coefficient of friction between soap and floor.

So, μ = F/N

Since F = 40 N and N = W = 493 N,

μ = F/N

μ = 40 N/493 N

μ = 0.081

So, the coefficient of friction between the soap and the floor is 0.081

Learn more about coefficient of friction here:

brainly.com/question/13923375

5 0

3 years ago

What cities (more than 1) has many fronts

Arisa [49]

Chattanooga - Chatype, London - Johnston, Berlin - BMF Change, Milan - Milano City, Eindhoven - Eindhoven, Stockholm - Stockholm Type, Minneapolis, and St. Paul - Twin.

6 0

3 years ago

_h2o2(aq)-_h2o(l) +o2(g)

zvonat [6]

Answer:

V02=9.78L

Explanation:

6 0

3 years ago