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sergeinik [125]
2 years ago
8

Which vehicle will have more kinetic energy, a parked semitruck or a car moving at 50 km/h?

Physics
1 answer:
Neporo4naja [7]2 years ago
3 0

Answer:

a semi truck

Explanation:

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In a drill during basketball practice, a player runs the length of the 30-meter court and back. The player does this three times
Sergeeva-Olga [200]

Answer:

0 m/s

Explanation:

Average velocity of an object is given by the net displacement divided by time taken. Displacement is equal to the shortest path covered by the object.

In this problem, a player runs the length of the 30-meter court and back. The player does this three times in 60 seconds.

As the player runs the court and returns to the original point. It would mean that the shortest path covered is 0.

Average velocity = displacement/time

v=0/30

v = 0 m/s

Hence, the correct option is (1).

6 0
3 years ago
The center of gravity of a loaded truck depends on how the truck is packed. If it is 4.0 m high and 2.4 m wide, and its CG is 2.
Vitek1552 [10]

The slope of the road can be given as the ratio of the change in vertical

distance per unit change in horizontal distance.

  • The maximum steepness of the slope where the truck can be parked without tipping over is approximately <u>54.55 %</u>.

Reasons:

Width of the truck = 2.4 meters

Height of the truck = 4.0 meters

Height of the center of gravity = 2.2 meters

Required:

The allowable steepness of the slope the truck can be parked without tipping over.

Solution:

Let, <em>C</em> represent the Center of Gravity, CG

At the tipping point, the angle of elevation of the slope = θ

Where;

tan\left(\theta \right) = \dfrac{\overline{AM}}{\overline{CM}}

The steepness of the slope is therefore;

\mathrm{The \ steepness \  of  \ the  \ slope}= \dfrac{\overline{AM}}{\overline{CM}} \times 100

Where;

\overline{AM} = Half the width of the truck = \dfrac{2.4 \, m}{2} = 1.2 m

\overline{CM} = The elevation of the center of gravity above the ground = 2.2 m

\mathrm{The \ steepness \  of  \ the  \ slope}= \dfrac{1.2}{2.2} \times 100 \approx 54.55\%

tan\left(\theta \right) = \mathbf{\dfrac{2.2}{1.2}} = \dfrac{11}{6}

Elevation \ of \ the \ road \ \theta = arctan\left( \dfrac{6}{11} \right)  \approx 28.6 ^{\circ}

The maximum steepness of the slope where the truck can be parked is <u>54.55 %</u>.

Learn more here:

brainly.com/question/20793607

3 0
2 years ago
Which situations are necessary components for malpractice to occur?
Yuri [45]

a. The risk of injury must be predictable.

b. A "breach of duty" is when a professional fails to uphold a level of care.

c. There must be a standard of care in place, and the practitioner must assume responsibility for the patient.

d. There must be a clear link between the treatment received and the harm.

<h3>What is malpractice?</h3>

Malpractice, commonly referred to as professional negligence, is defined as "an incident of carelessness or incompetence on the part of a professional" under tort law.

The following professionals might be the target of malpractice claims:

Medical professionals: If a doctor or other healthcare practitioner does not exercise the level of care and competence that a similarly situated professional in the same medical field would deliver under the circumstances, a medical malpractice claim may be made against them.

Lawyers: Failure to provide services with the amount of competence, care, and diligence that a reasonable lawyer would use in the same situation may be grounds for a legal malpractice claim.

To know more about malpractice, visit;

brainly.com/question/25441985

#SPJ4

3 0
1 year ago
The normal boiling point of cyclohexane is 81.0 ℃. what is the vapor pressure of cyclohexane at 81.0 ℃?
Hitman42 [59]
The boiling point is defined as the temperature at which the pressure of the vapor of the liquid is equivalent to the external atmospheric pressure surrounding the liquid. Therefore, the boiling point of the liquid is dependent on the atmospheric pressure.

Based on this, the vapor pressure of cyclohexane at 81 degrees celcius will be equal to atmospheric pressure (based on barometric readings)<span />
6 0
2 years ago
If you release a weight and allow it to fall under the influence of gravity alone, what kind of motion will it experience?
fgiga [73]
The object is in free fall when and only when it is being affected by gravity alone.  It is not being influenced by a significant amount of air resistance will always be in free fall.  F(net)/m = acceleration
8 0
3 years ago
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