Answer:
9
Step-by-step explanation:
-27/-3
27/3 is 9
each of them have a negative so it stays positive
9
Answer:
- domain: (-4, ∞)
- range: [-4, ∞)
Step-by-step explanation:
The domain is the horizontal extent of the function. This function is defined for all values of x greater than (but not including) -4. Its domain is (-4, ∞).
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The range is the vertical extent of the function. This function gives output values of any number greater than or equal to -4. Its range is [-4, ∞).
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Interval notation uses square brackets when the value is included in the interval. It uses round brackets (parentheses) when the end value is not included in the interval. ∞ is not a number, so that end always gets a round bracket.
To tessellate a surface using a regular polygon, the interior angle must be a sub-multiple (i.e. factor) of 360 degrees to cover completely the surface.
For a regular three-sided polygon, the interior angle is (180-360/3)=60 °
Since 6*60=360, so a regular three-sided polygon (equilateral triangle) tessellates.
For a regular four-sided polygon, the interior angle is (180-360/4)=90 °
Since 4*90=360, so a regular four-sided polygon (square) tessellates.
For a regular five-sided polygon, the interior angle is (180-360/5)=108 °
Since 360/108=3.33... (not an integer), so a regular five-sided polygon (pentagon) does NOT tessellate.
For a regular six-sided polygon, the interior angle is (180-360/6)=120 °
Since 3*120=360, so a regular six-sided polygon (hexagon) tessellates.
Answer: Ratio of black horses to all horses = 59/62
Step-by-step explanation:
Total number of horses = 62
Total number of white horses = 3
Assuming that the rest horses are black. That means the total number of black horses would be 62-3 =59. So there are 59 black horses and there are 3 white horses.
Ratio of black horses to all horses will be the total number of black horses / the total number of horses.
Ratio of black horses to all horses
= 59/62 or 59:62
It can also be expressed in decimals which will become
0.952
Sent a picture of the solution to the problem (s).
