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4 years ago

10 points and brainlyest if possible and right.

Physics

1 answer:

Delicious77 [7]4 years ago

6 0

THE answer the table is holding the book up would be a normal force

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AgNO3(aq)+NaCl(aq)—>|NaN03(aq)+AgCl(s)

ASHA 777 [7]

the answer to the question is (D)

8 0

4 years ago

30 POINTS!!! PLZZZZZZ HELP

lesya [120]

Psychological disorder is a kind of disease, related to brain functioning, they are very different, but can't be distinguished at high level so they are not extremely different

In short, Your Answer would be: "False"

Hope this helps!

7 0

3 years ago

Read 2 more answers

Three pendulums all have the same length and start from the same height. The first pendulum is very light and has a mass of 67 g

vovikov84 [41]

Answer:

All three pendulum will attain same velocity

Explanation:

All three pendulum will attain same velocity irrespective of their mass difference in isolated system (means where air drag are negligible) and at same length

As you know when velocity is calculated we can not take mass into account.

3 0

3 years ago

Salmon often jump waterfalls to reach their breeding grounds. Starting downstream, 2.33 m away from a waterfall 0.488 m in heigh

Ulleksa [173]

Answer:

5.68 m/s

Explanation:

The motion of the salmon is the same as a projectile: it is launched with an initial speed $u$ at an angle of $\theta=38^{\circ}$ above the horizontal.

The motion of the salmon consists of two indipendent motion:

- Along the horizontal direction, it is a uniform motion with constant velocity

$v_x = u cos \theta$

So that the distance travelled is

$d=v_x t = u cos \theta t$ (1)

- Along the vertical direction, it is a uniformly accelerated motion with constant acceleration downward, so the vertical displacement is

$y = u sin \theta t - \frac{1}{2}gt^2$ (2)

where g is the acceleration of gravity.

We know the following:

- The horizontal distance travelled by the salmon to reach the waterfall is

d = 2.33 m

- The vertical distance travelled is the height of the waterfall,

y = 0.488 m

From (1) we get:

$t=\frac{d}{u cos \theta}$

And substituting into (2), we can solve the equation to find t, the time at which the salmon reaches the waterfall:

$y = u sin \theta \frac{d}{u cos \theta} - \frac{1}{2}gt^2 = d tan \theta - \frac{1}{2}gt^2\\t = \sqrt{\frac{2(d tan \theta - y)}{g}}=\sqrt{\frac{2(2.33 tan 38^{\circ}-0.488)}{9.81}}=0.521 s$